How do I do the bus stop method?
1 answer:
The bus stop method is just like division.
Ex
137÷5=
1.) 5 goes into one zero times so there is a zero on top.
2.) 5 goes into 13 two times, so after the zero there is a 2.
3.) 5 goes into 37 seven times so there is a 7 after the 2.
4.) There is a 2 left and five can't go into school therefore that is a remainder.
027R2
5/137
<u>- 10</u>
37
<u>-35</u>
2
Hoped I helped:D
Ex
137÷5=
1.) 5 goes into one zero times so there is a zero on top.
2.) 5 goes into 13 two times, so after the zero there is a 2.
3.) 5 goes into 37 seven times so there is a 7 after the 2.
4.) There is a 2 left and five can't go into school therefore that is a remainder.
027R2
5/137
<u>- 10</u>
37
<u>-35</u>
2
Hoped I helped:D
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Answer:
Step-by-step explanation:
A circle centered at (0,0) with radius r is
Since your circle has diameter of 12, then its radius is 6. Then
So a possible answer is:
If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:
The center of this circle would be (-4, 0) which is still on the x-axis.
Given:
The expression is:
It leaves the same remainder when divided by x -2 or by x+1.
To prove:
Solution:
Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).
Let the given polynomial is:
It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that
...(i)
Substituting in the given polynomial.
Substituting in the given polynomial.
Now, substitute the values of P(2) and P(-1) in (i), we get
Divide both sides by 3.
Hence proved.