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alina1380 [7]
3 years ago
9

Complete the following steps.

Chemistry
1 answer:
vovikov84 [41]3 years ago
4 0

Answer:

See explanation

Explanation:

a) The balanced reaction equation is;

K2S + CO(NO3)2 ------> COS + 2 KNO3

b) When we include the states of matter, we have;

K2S(aq) + CO(NO3)2(aq) ----> COS(s) + 2 KNO3(aq)

c) The complete ionic equation is;

2K^+(aq) + S^2-(aq) + Co^2+(aq) + 2NO3^-(aq) ----> CoS(s) + 2K^+(aq) + 2NO3^-(aq)

Net ionic equation;

Co^2+(aq) + S^2-(aq) ----> CoS(s)

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The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute th
MrRissso [65]

The question is incomplete, complete question is :

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

\frac{K_1}{K_2}=?

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol

Answer:

0.4284 is the ratio of the rate constants.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

The expression used with catalyst and without catalyst is,

\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}

\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}

where,

K_2 = rate constant reaction -1

K_1 = rate constant reaction -2

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol = 14,000 J

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol = 11,900 J

R = gas constant = 8.314 J/ mol K

T = temperature = 25^oC=273+25=298 K

Now put all the given values in this formula, we get

\frac{K_1}{K_2}=e^{\frac{11,900- 14,000Jl}{8.314 J/mol K\times 298 K}}=2.3340

0.4284 is the ratio of the rate constants.

7 0
3 years ago
What is one way compounds can be categoriezed​
Katena32 [7]

Answer:

Explanation:

Compounds can be classified as ionic or covalent. Molecules are the simplest unit of a covalent compound, and molecules can be represented in many different ways.

hope this helps (:

3 0
3 years ago
When making calculations, you should rely on the precision of your measured data.
ELEN [110]
True 

Im happy i could help you today 

have a great rest of ur week :)
3 0
3 years ago
Calcium chloride, CaCl2, is commonly used as an electrolyte in sports drinks and other beverages, including bottled water. A sol
zhannawk [14.2K]

Answer:

Mole percent of CaCl_{2} in solution is 1.71%

Explanation:

Number of moles of a compound is the ratio of mass to molar mass of the compound.

Molar mass of CaCl_{2} = 110.98 g/mol

Molar mass of H_{2}O = 18.02 g/mol

Density is the ratio of mass to volume

So, mass of 60.0 mL of water = (60\times 0.997)g=60.8g

Hence, 6.50 g of CaCl_{2} = \frac{6.50}{110.98}moles of CaCl_{2} = 0.0586 moles of CaCl_{2}

60.8 g of H_{2}O= \frac{60.8}{18.02}moles of H_{2}O = 3.37 moles of H_{2}O

So, mole percent of CaCl_{2} in solution = \frac{n_{CaCl_{2}}}{n_{total}}\times 100% = \frac{0.0586}{0.0586+3.37}\times 100% = 1.71%

5 0
4 years ago
Why are units of measurement useful?
natali 33 [55]

Answer:

B

Explanation:

If you are comparing an amount you are trying to find the quantity or the total of something or the size  therefore answer B is the right answer  

4 0
3 years ago
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