The energy of the light with a wavelength of 415 nm is not sufficient to remove an electron from a silver atom in the gaseous phase.
<h3>Energy and wavelength of light</h3>
The energy and wavelength of light are related by the formula given below:
- Energy = hc/λ
- where, E = energy
- h = Planck's constant
- c = velocity of light
- λ = wavelength of light
<h3>Calculating the energy of the light</h3>
From the data provided:
- h = 6.63 × 10^-34 Js
- c = 3.0 × 10^8 m/s
- λ = 415 nm = 4.15 × 10^-7 m
E = (6.63 × 10^-34 × 3.0 × 10^8 m/s)/4.15 × 10^-7 m
E = 4.79 × 10^-19 J
Energy of light is 4.79 × 10^-19 J
Compared with the ionization energy of silver, the energy of the light is far less.
Therefore, the energy of the light with a wavelength of 415 nm is not sufficient to remove an electron from a silver atom in the gaseous phase.
Learn more about about ionization energy and energy of light at: brainly.com/question/14596067
Answer:
8 OH⁻(aq) + Mn(s) ⇒ MnO₄⁻(aq) + 4 H₂O(l) + 7 e⁻
Explanation:
Let's consider the following oxidation half-reaction that takes place in basic aqueous solution.
Mn(s) ⇒ MnO₄⁻(aq)
First, we will perform the mass balance. We will add 4 H₂O to the products side and 8 OH⁻ to the reactants side.
8 OH⁻(aq) + Mn(s) ⇒ MnO₄⁻(aq) + 4 H₂O(l)
Finally, we will perform the charge balance by adding 7 electrons to the products side.
8 OH⁻(aq) + Mn(s) ⇒ MnO₄⁻(aq) + 4 H₂O(l) + 7 e⁻
Answer:
pH = 2 and pOH = 12
Explanation:
Given [OH⁻] = 1 x 10⁻¹²M
pOH = -log[OH⁻] = -log(1 x 10⁻¹²) = - ( -12 ) = 12
pH + pOH = 14 => pH = 14 - pOH = 14 - 12 = 2
