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krok68 [10]
3 years ago
15

PLS HELP 6TH GRADE ITS ONE QUESTION ABOUT SCIENCE

Chemistry
2 answers:
myrzilka [38]3 years ago
7 0

Your answer would be C. :)

julia-pushkina [17]3 years ago
5 0

Answer: The answer is C

Explanation:

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6 0
3 years ago
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When 0.215 mol of a gas is placed into a 34.25 mL container at 125.0°C, 1
horrorfan [7]

Answer:

205.12 atm

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

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R = 0.0821 Latm/perK)

T = temperature (K)

n = number of moles (mol)

According to the information in this question;

P = ?

V = 34.25 mL = 34.25 ÷ 1000 = 0.03425L

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T = 125.0°C = 125 + 273 = 398K

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P = nRT ÷ V

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P = 7.025 ÷ 0.03425

P = 205.12 atm

8 0
3 years ago
What happens to the partial pressure of oxygen in a sample of air if the temperature is increased?
ludmilkaskok [199]

Air is mainly composed of N2  (78%), O2 (21%) and other trace gases. Now, the total pressure of air is the sum of the partial pressures of the constituent gases. The partial pressure of each gas, for example say O2, can be expressed as:

p(O2) = mole fraction of O2 * P(total, air)  ----(1)

Thus, the partial pressure is directly proportional to the total pressure. If we consider a sealed container then, as the temperature of air increases so will its pressure. Based on equation (1) an increase in the pressure of air should also increase the partial pressure of oxygen.

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