Can anyone help me with this, I gave a picture so you can figure it out

Mathematics

1 answer:

Ivenika [448]3 years ago

6 0

Answer:

X=2

Step-by-step explanation:

If the smaller triangle's base is 1.5ft and the bigger triangle's base is 6ft then in order to find x you have to find how much bigger the big triangle is compared to the small triangle in order to do that you have to divide 6 by 1.5 (6÷1.5) which is 4 now you know that the bigger triangle is 4 times as big as the smaller triangle now to find X divide the 8 by 4 (since the 8 is on the same side as the X only the 8 is on the bigger triangle) which is 2

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The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea

anyanavicka [17]

Hello !
If you mist find the area of the rhombus,you need to calculate the length of the diagonals.

We have the rhombus ABCD.The diagonals are are AC and BD .
<span>Here's a formula to find out the distance between two points in the Cartesian system : (let's take randomly 2 point and their coordinates)
</span>
<span> M (m₁,m₂) ; N (n₁,n₂) ⇒ MN = \sqrt{ (m_{1} - n_{1})^{2} + (m_{2} - n_{2})^{2} }
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Now it's simple to calculate the diagonals :

$AC = \sqrt{ (-4-6)^{2} +(-2-8)^{2}} \\ \\ AC= \sqrt{ (-10)^{2} + (-10)^{2} } \\\\AC = \sqrt{ 100+100} \\\\ AC =\sqrt{ 200 } \\\\AC=10 \sqrt{2} \\ \\ \\ BD = \sqrt{ (-2-4)^{2} + 6^{2} } \\\\BD=\sqrt{ (-6)^{2} + 6^{2} }\\\\BD= \sqrt{6^{2}+6^{2}} \\\\BD= \sqrt{36+36} \\\\BD= \sqrt{72} \\\\BD=6 \sqrt{2}$

The area is : $\frac{AC*BD}{2} = \frac{ 10\sqrt{2} * 6\sqrt{2} }{2} = \frac{60*2}{2} =60$

Answer: 60 u²

The representation is below.
Have a nice day :)

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Bad White [126]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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