The current altitude of the plane is 15400 feet above the ground and the plane's horizontal distance to the airport is 200000 mi
les away. What angle of depression must the pilot make on his descent in order to safely land on the runway>
1 answer:
Answer:
0.441°
Step-by-step explanation:
tan = 1540/200000
tan = 0.0077
tan-1(0.0077) = 0.441
angle of depression is 0.0441°
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