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Inessa [10]
3 years ago
5

A Sociology instructor gives students points for each​ discussion-board post and points for each reply to a post. Ana wrote 6 po

sts and 8 replies and received 114 points. Jae wrote 5 posts and 4 replies and received 79 points. Determine how many points a discussion post is worth and how many points a reply is worth?
Mathematics
1 answer:
Naya [18.7K]3 years ago
8 0

Answer:

5 points per post and 2 points per replies

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Help me correct this plz
adelina 88 [10]
The answer will be D) 75

To find this it’s easiest to find how many animals there are per percent. So to find this you simply have to divide 30 (the number of cats) by 40 (the percent that makes up) to find the number of animals per percent.

30/40

.75

Then you multiply this by 100 to find how many animals there are total.

.75(100)

75

5 0
3 years ago
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How to type a line above the number 6 on chromebook.
hjlf

Answer:

you put in the number 6 but you leave room uptop so enter and then put 6 for the----- so in other words

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8 0
2 years ago
you got a new credit card with an interest rate of 18% compounded monthly and no minimum payment. you go on a shopping spree and
just olya [345]
The total amount owed after 6 months will be found using the formula:
FV=P(1+r/100*n)^n
P=principle=$10000
r=rate=18%
n=terms=0.5


FV=10000(1+18/2*100)^0.5
FV=$10,440.30651
Thus the amount owed will be $10440.30651
7 0
3 years ago
7×8/10= the product lies between?
Lisa [10]
7 X 8/10=5.6 Provided the / meaning division.

6 0
3 years ago
Simplify the expression below and write it as a single logarithm:
OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

<u>Solution:</u>

Given, expression is 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

Rearranging the terms we get,

\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)

\text { since a } \times \log b=\log \left(b^{a}\right)

\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)

\text { We know that } \log a \times \log b=\log a b

\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.

\text { We know that } \log a-\log b=\log \frac{a}{b}

\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

Hence, the simplified form \rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

4 0
3 years ago
Read 2 more answers
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