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Marat540 [252]
3 years ago
9

A sample of NaNo3 weighing 0.38g is placed in 50.0mL volumetric flask.The flask is then filled with water to the mark on the nec

k,dissolving the solid.What is the molarity of the resulting solution.
Chemistry
1 answer:
snow_tiger [21]3 years ago
5 0

Answer:

0.0894 M

Explanation:

So you first want to change the grams into moles (since molarity is moles solute per Liter solution).

The molar mass of NaNO3 is 84.995 g/mol, so we divide 0.38g of NaNO3 by 84.995 g/mol to get approximately 0.004471 mol NaNO3.

Now, all you have to do is to divide by the total Liters of water (your solution).

Since the volume is expressed in mL, you just need to divide by 1000 (1 L = 1000mL) to get 0.050 L solution.

Therefore, to get molarity, you divide 0.004471 mol by 0.050 L to get your answer of 0.0894 M.

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You carefully weigh out 20.00 g of CaCO3 powder and add it to 81.00 g of HCl solution. You notice bubbles as a reaction takes pl
Zepler [3.9K]

Answer:

The relevant equation is:

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

Explanation:

1 mol of calcium carbonate can react to 2 moles of Hydrochloric acid to produce 1 mol of water, 1 mol of calcium chloride and 1 mol of carbon dioxide.

The formed CO₂ is the reason why you noticed bubbles as the reaction took place

3 0
3 years ago
PLEASEE HELP ME!!!!!
Yakvenalex [24]

Answer:

Explanation:

8.61+5.779 = 14.389 = 1.4389 × 10^1

25 - 12.5 = 1.25 x 10^1

56.35 / 13.2 = 4.2689

6 0
2 years ago
You have a 15.0 gram sample of gold at 20.0°C. How much heat does it take to raise the temperature to 100.0°C?
Nadusha1986 [10]

Answer:

=154.8 J

Explanation:

The rise in temperature is contributed by the change in temperature.

Change in enthalpy = MC∅,  where M is the mass of the substance, C is the specific heat capacity and ∅ is the change in temperature.

Change in temperature = 100.0°C-20.0°C=80°C

ΔH=MC∅

The specific heat capacity of gold= 0.129 J/g°C

ΔH= 15.0g×0.129J/g°C×80°C

=154.8 J

7 0
3 years ago
The percent composition of calcium is ?
DochEvi [55]

Answer: 40.1%

Explanation: The mass of calcium in this compound is equal to 40.1 grams because there's one atom of calcium present and calcium has an atomic mass of 40.1 . The molar mass of the compound is 100.1 grams. Using the handy equation above, we get: Mass percent = 40.1 g Ca⁄100.1 g CaCO3 × 100% = 40.1% Ca.

5 0
3 years ago
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Dmitriy789 [7]
Answer:

Trade winds


Explanation:

I am not sure
7 0
2 years ago
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