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3 years ago

1. Which of the following qualifies as a Bronsted-Lowry base but not an Arrhenius base?

Chemistry

2 answers:

jarptica [38.1K]3 years ago

8 0

Acids lose H+ and bases gain H+

Luden [163]3 years ago

5 0

Arrhenius Theory: according to Arrhenius, acid is one that can donate proton in an aqueous solution, while base is one that can donate hydroxide ion in an aqueous solution.

Bronsted-Lowry Theory: according to Bronsted Lowry, acid is one that can donate protons while base is one that can accept a proton.

1. In first, only C. NH3 can't give hydroxide ion, but can accept a proton so it is a Bronsted-Lowry Base but not an Arrhenius base.

2.In second, as the definition suggested, bronsted base is one that can accept protons and acid is one that can loose protons. so answer is D. Acids lose H+ and bases gain H+.

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In order: tilted, rotates, revolving.

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2 years ago

(6) Compare a CSTR with a PFR below. a. A flow of 0.3 m3/s enters a CSTR (volume of 200 m3) with an initial concentration of spe

Dmitry [639]

Answer:

Explanation:

Given that:

The flow rate Q = 0.3 m³/s

Volume (V) = 200 m³

Initial concentration $C_o$ = 2.00 ms/l

reaction rate K = 5.09 hr⁻¹

Recall that:

$time (t) = \dfrac{V}{Q}$

$time (t) = \dfrac{200}{0.3}$

$time (t) = 666.66 \ sec$

$time (t) = \dfrac{666.66 }{3600} hrs$

$time (t) = 0.185 hrs$

$\text{Using First Order Reaction:}$

$\dfrac{dc}{dt}=kc$

where;

$t = \dfrac{1}{k} \Big( \dfrac{C_o}{C_e}-1 \Big)$

$0.185 = \dfrac{1}{5.09} \Big ( \dfrac{200}{C_e}- 1 \Big)$

$0.942 = \Big ( \dfrac{200}{C_e}- 1 \Big)$

$1+ 0.942 = \Big ( \dfrac{200}{C_e} \Big)$

$\dfrac{200}{C_e} = 1.942$

$C_e = \dfrac{200}{1.942}$

$\mathbf{C_e = 102.98 \ mg/l}$

Thus; the concentration of species in the reactant = 102.98 mg/l

b). If the plug flow reactor has the same efficiency as CSTR, Then:

$t _{PFR} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{5.09} \Big [ In ( \dfrac{200}{102.96}) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} =0.196 \Big [ In ( 1.942) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} =0.196(0.663)$

$\dfrac{V_{PFR}}{0.3 hrs} =0.196(0.663)$

$\dfrac{V_{PFR}}{0.3*3600 sec} =0.196(0.663)$

$V_{PFR} =0.196(0.663)*0.3*3600$

$V_{PFR} = 140.34 \ m^3$

The volume of the PFR is ≅ 140 m³

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3 years ago

Isotopes of elements have different:

Morgarella [4.7K]

Isotopes of elements have same atomic numbers and different mass number(atomic masses).

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2 years ago

Perform the following metric conversions: Please explain bc I really dont get it at ALL !!!!

makkiz [27]

Answer:

0.2007 nm

3.57 cm

0.01478 g

8280000 pg

Explanation:

1)200.7 pm

1 picometer is equal to 0.001 nanometer.

1 nm = 1000 pm

200.7 pm× 1 nm / 1000 pm = 0.2007 nm

2)0.000357 hm

1 hectometer is equal to 10,000 centimeter.

1 hc = 10,000 cm

0.000357 hc× 10,000 cm / 1 hc = 3.57 cm

3) 14.78 mg

1 gram is equal to 1000 milligram.

1 g = 1000 mg

14.78 mg × 1 g/1000 mg = 0.01478 g

4)8.280 µg

1 microgram is equal to 10⁶ picogram.

1 µg = 1000000 pg

8.280 µg× 10⁶ pg/ 1µg = 8.280×10⁶ pg or 8280000 pg

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3 years ago

What are the two parts of the third Step?

spin [16.1K]

Answer:

Explanation:

7 0

2 years ago

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