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2 years ago

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A child has 48 quarters and 80 dimes. The child wishes to stack the coins so that each stack has the same number of coins, and e

ach stack contains only one kind of coin. What is the
largest number of coins that the child can place in each stack?

1 answer:

Crank2 years ago

4 0

Since the greatest common factor for 48 and 80 is 16 then we conclude the largest number of stack is 16

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Please I’m struggling

insens350 [35]

Answer:

1080cm²

Step-by-step explanation:

surface area=sum of the area of all the shapes

area of triangle=1/2*base*height

1/2*24*10=120*2(because there are two triangles)=240cm²

10*14=140cm²

24*14=336cm²

Area of slanting figure=26*14=364cm²

add all the results

240+140+336+364=1080cm²

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2 years ago

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Mrs. Gomes found that 40% of students at her high school take chemistry. She randomly surveys 12 students. What is the probabili

VMariaS [17]

Binomial formula is :
$P ( k = 4 ) = nCk * p ^{k}(1-p) ^{n}= \\ =495 * 0.4 ^{4}* ( 0.6 ) ^{8}=$
= 495 * 0.0256 * 0.0167961 =
= 0.21284 ≈ 0.213
Answer: C ) 0.213

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3 years ago

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

astra-53 [7]

$\sqrt{5}$

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2 years ago

Find the coordinats of P

Crazy boy [7]

$\textit{internal division of a line segment using ratios} \\\\\\ A(8,6)\qquad B(-2,-9)\qquad \qquad \stackrel{\textit{ratio from A to B}}{3:2} \\\\\\ \cfrac{A\underline{P}}{\underline{P} B} = \cfrac{3}{2}\implies \cfrac{A}{B} = \cfrac{3}{2}\implies 2A=3B\implies 2(8,6)=3(-2,-9)$

$(\stackrel{x}{16}~~,~~ \stackrel{y}{12})=(\stackrel{x}{-6}~~,~~ \stackrel{y}{-27})\implies P=\underset{\textit{sum of the ratios}}{\left( \cfrac{\stackrel{\textit{sum of x's}}{16-6}}{3+2}~~,~~\cfrac{\stackrel{\textit{sum of y's}}{12-27}}{3+2} \right)} \\\\\\ P=\left( \cfrac{10}{5}~~,~~\cfrac{-15}{5} \right)\implies P=(2~~,~~-3)$

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2 years ago

Brian irons 2/9 of his shirt in 3 3/5 minutes. At this rate, how much of his shirt does he iron each minute?

vodka [1.7K]

The speed for which Brian iron the shirts is given by:

$R = \frac{\frac{2}{9}}{3\frac{3}{5}}$

Rewriting we have:

$R = \frac{\frac{2}{9}}{\frac{18}{5}}$

$R = \frac{10}{162}$

Then, for each minute, we have the amount of ironed shirt is:

$(\frac{10}{162})(1) = \frac{10}{162}$

Answer:

At this rate, Brian plans 10/162 of his shirt.

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