A child has 48 quarters and 80 dimes. The child wishes to stack the coins so that each stack has the same number of coins, and e
ach stack contains only one kind of coin. What is the
largest number of coins that the child can place in each stack?
1 answer:
Since the greatest common factor for 48 and 80 is 16 then we conclude the largest number of stack is 16
You might be interested in
Answer:
x is 60⁰ because 180 - 40 is 120 divide it by 2 because the bottem angles are equal and u get 60
Answer:
Im choosing A and yes that would be great
Step-by-step explanation:
Answer:
(x - 9)(x + 4)
Step-by-step explanation:
x^2−5x−36
As you know, -36 = -9 * 4 and (-9) + 4 = -5
so Factor
= (x - 9)(x + 4)
Answer:
c. x=3
Step-by-step explanation:
Given:
7x < 21
Divide both sides by 7
7x / 7 < 21 / 7
x < 21/7
x < 3
x = 3
Check:
7x < 21
7(3) < 21
21 = 21
W = 21 - 3
weight of the tree = 21 pounds - 3 pounds
