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3 years ago

What is the answer to -9(k + 9) - 8

Mathematics

2 answers:

OLga [1]3 years ago

6 0

-9k-81-8

-9k-89
Hope it helps

MAVERICK [17]3 years ago

5 0

Answer:

-9k - 89.

Step-by-step explanation:

-9(k + 9) - 8

Simplifying by distributing the -9 over the brackets:

= -9k - 81 - 8

= -9k - 89.

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Find the x will name brainlist

Alenkasestr [34]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

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To solve these type of problems you need to use the pythagoras theorem ⇨ Hypotenuse² = Base² + Altitude².

Here,

Altitude = 1.6 cm.
Base = 1.2 cm
Hypotenuse = x

Now, let's solve for x.

Hypotenuse² = Base² + Altitude²

x² = (1.2)² + (1.6)²

x² = 1.44 + 2.56

x² = 4

x = √4

x = 2.

So, the value of x is 2 cm.

Pythagoras theorem can be used only in the cases of right-angled triangles. Here, it's given that the triangle is right angled so we can use this theorem.
To solve the squares if decimals, take them as whole numbers & then just add the decimal points. For example, ⇨ for (1.2)², take it as 12² , then multiply 12 by 12, you'll get 144. Now, add the decimal place accordingly ⇨ 1.44 . So, (1.2)² = 1.44.

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3 years ago

What is 7,390.7 divided by 0.874 ?

Alinara [238K]

About 8,456.17849
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3 years ago

If you run for 0.4 hours at 7 mph, how fast should you walk during the next 0.8 hours to have the average speed of 5 mph?

Fantom [35]

Answer:

4 mph

Step-by-step explanation:

The average speed of an object is given by the total distance covered by the time taken:

$v=\frac{d}{t}$

where

d is the total distance covered

t is the time taken

in the first part, the person runs for 0.4 hours at a speed of 7 mph, so the distance covered in the 1st part is

$d_1 = v_1 t_1 = (7)(0.4)=2.8 mi$

Then the distance covered in the second part is $d_2$ , so the total distance is

$d=2.8+d_2$ (1)

The total time elapsed is 0.4 hours (first part) + 0.8 hours (second part), so

$t=0.4+0.8=1.2 h$

So we can write the average speed as

$v=\frac{2.8+d_2}{1.2}$ (1)

We want the average speed to be 5 mph,

v = 5 mph

Therefore we can rearrange eq.(1) to find d2:

$d_2 = 1.2v-2.8 = (1.2)(5)-2.8=3.2 mi$

And therefore, the speed in the second part must be

$v_2=\frac{d_2}{t_2}=\frac{3.2}{0.8}=4 mph$

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3 years ago

I really need helpppppp I’m confused

Natasha2012 [34]

Add 35+ 72.5=107.5 that should give you your answer for c and the answer for d is acute because the triangle would have to be 360 to be Obtused and it's not a right triangle because you don't have a 90 degree angle

4 0

3 years ago

What are the zeros of this polynomial and state their multiplicity at each y=(x-5)(x+2)^2

N76 [4]

Answer:

Step-by-step explanation:

The zeros of a polynomial are the x-intercepts of the function. To find them, we factor the polynomial and set each factor equal to 0.

This polynomial is already factored so set each to 0 and solve for x.

$x-5=0\\x=5\\(x+2)^{2}=0 \\(x+2)=0\\x=-2$

This means x=-2, 5. Each zero or root has a multiplicity - the number of times the factor occurs. This is also known as the exponent of the factor expression.

(x+5) occurs once since it has exponent 1.

$(x+2)^{2}$ occurs twoce since it has exponent 2.

x=5 mult. 1, x=-2 mult. 2

7 0

3 years ago