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german
3 years ago
8

What is the answer to -9(k + 9) - 8

Mathematics
2 answers:
OLga [1]3 years ago
6 0
-9k-81-8

-9k-89
Hope it helps
MAVERICK [17]3 years ago
5 0

Answer:

-9k - 89.

Step-by-step explanation:

-9(k + 9) - 8

Simplifying by distributing the -9 over the brackets:

= -9k - 81 - 8

= -9k - 89.

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Mario has read two less than four times the number of books Tonya has read. what factored expression represents the number of bo
igor_vitrenko [27]
Let X be the variable used to represent the expression of the total number of books that Mario has read.
We used 4X to represent "four times the number of books". Then we add -2 to interpret the words "for two less than".
Therefore, we have an expression of 4X-2 for the total number of books that Mario has read.

8 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
Angie and Kenny play online video games. Angie buys 1 software package and 1month of gameplay. Kenny buys 1 software package and
MakcuM [25]

Answer:

10$ I think

Step-by-step explanation:

2*30=60

90-60=30

30/3=10

5 0
3 years ago
6x+9=-12<br> Can someone help me with this question
Amiraneli [1.4K]

Answer:

-7/2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
(80 + 240 times 3) ÷ 20<br><br> Solve the equation
shutvik [7]
240x3= 720

720+80 = 800

800/20= 40

The answer is 40.

Tell me if this helps
Please mark me as brainliest
8 0
2 years ago
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