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3 years ago

HELP HELP HELP HELP HELP HELP HELP HELP HELP write a brief summer about inequalities on a number line .

Mathematics

1 answer:

g100num [7]3 years ago

4 0

Answer:

To plot an inequality, such as x>3, on a number line, first draw a circle over the number (e.g., 3). Then if the sign includes equal to (≥ or ≤), fill in the circle. If the sign does not include equal to (> or <), leave the circle unfilled in.

Step-by-step explanation:

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Please help, I’m confused. I think it’s SAS but I’m not sure if it’s SSA

OLga [1]

The answer to the maths equation is SAS

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3 years ago

If CP =Rs. 9,000 and SP= Rs. 8,584 then Profit / loss amount is

Gemiola [76]

Answer: Loss = Rs. 416

Step-by-step explanation:

Since CP is more than SP, it is a loss.

Loss = CP - SP

Loss = 9000 - 8584

Loss = 416

8 0

3 years ago

Determine whether the relation is a function.<br><br> (-3,3), (-2,2), (-1,1), (1,-1), (2,-2), (3,-3)

Luba_88 [7]

Answer:

Function

Step-by-step explanation:

Because there is an output for every input listed of its opposite.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge

BabaBlast [244]

$\underline{\bf{Given \:equation:-}}$

$\\ \sf{:}\dashrightarrow ax^2+by+c=0$

$\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.$

$\sf We\:know,$

$\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}$

$\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}$

$\underline{\large{\bf Identities\:used:-}}$

$\boxed{\sf (a+b)^2=a^2+2ab+b^2}$

$\boxed{\sf (√a)^2=a}$

$\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}$

$\boxed{\sf \sqrt{\sqrt{a}}=a}$

$\underline{\bf Final\: Solution:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}$

$\bull\sf Apply\: Squares$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}$

$\bull\sf Put\:values$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}$

$\bull\sf Simplify$

$\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}$

$\underline{\bf More\: simplification:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}$

$\underline{\Large{\bf Simplified\: Answer:-}}$

$\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}$

5 0

2 years ago

Read 2 more answers

A school director Must randomly select 6 teachers to participate in a training session there are 30 teachers at the school in ho

Ede4ka [16]

Solution:

we are given that

A school director Must randomly select 6 teachers to participate in a training session there are 30 teachers at the schoo. The order of selection does not matter.

As we know

6 teacheras can be selected out of 30 teacher in ${30}_C_6$ ways.

${30}_C_6=\frac{30!}{6!24!}\\
\\ {30}_C_6=\frac{25*26*27*28*29*30}{1*2*3*4*5*6}\\
\\ {30}_C_6=593775$

Hence the required number of ways is 593775.

7 0

3 years ago