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slava [35]
3 years ago
10

1) Hank is looking to sell his motorcycle. He compiles these prices from the newspaper for bikes just like his

Mathematics
1 answer:
Step2247 [10]3 years ago
8 0

Answer:

The median

Step-by-step explanation:

If you look at the sample section of the 5 different prices, you can see that $2,000 is very far away from the rest of the prices, which range from $14,000 to $17,000. This $2,000 is an outlier, and is likely not accurate in predicting reasonable prices for Hank's bike, so it should not be a factor in his decision or contribute to the mean value.

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Find the variable of each ............
QveST [7]

Answer:

The answer is option d.

To find a we have to first find b

sin 60° = b / 10

b = 10 sin 60°

b = 5√3

sin 30° = b / a

b = 5√3

a = 5√3 sin 30°

a = 10√3

cos 30° = c / a

a = 10√3

c = 10√3 sin 30°

c = 15

cos 60° = d /10

d = 10 cos 60°

d = 5

a = 10√3 , b = 5√3 , c = 15 and d = 5

Hopethis helps.

4 0
3 years ago
Which expression is equivalent to -2(5x -0.75)?
grin007 [14]

Answer:

-10x + 1.5

Step-by-step explanation:

-2(5x-0.75)

-10x+1.5

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

#

6 0
3 years ago
Use a half-angle identity to find the exact value
Tatiana [17]

Given:

\cos 15^{\circ}

To find:

The exact value of cos 15°.

Solution:

$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}

Using half-angle identity:

$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}

$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}

Using the trigonometric identity: \cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}

            $=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}

Let us first solve the fraction in the numerator.

            $=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}

Using fraction rule: \frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}

            $=\sqrt{\frac {2+\sqrt{3}}{4}}

Apply radical rule: \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

           $=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}

Using \sqrt{4} =2:

           $=\frac{\sqrt{2+\sqrt{3}}}{2}

$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}

5 0
3 years ago
If angle ABC is one degree less than three times angle ABD and angle DBC=47 find each measure
Contact [7]

It has not been indicated whether the figure in the questions is a triangle or a quadrilateral. Irrespective of the shape, this can be solved. The two possible shapes and angles have been indicated in the attached image.

Now, from the information given we can infer that there is a line BD that cuts angle ABC in two parts: angle ABD and angle DBC

⇒ Angle ABC = Angle ABD + Angle DBC

Also, we know that angle ABC is 1 degree less than 3 times the angle ABD, and that angle DBC is 47 degree

Let angle ABD be x

⇒ Angle ABC = 3x-1

Also, Angle ABC = Angle ABD + Angle DBC

Substituting the values in the above equations

⇒ 3x-1 = x+47

⇒ 2x = 48

⇒ x = 24

So angle ABD = 24 degree, and angle ABC = 3(24)-1 = 71-1 = 71 degree

8 0
3 years ago
9 + 15m<br><br><br><br>factorisation of algebraic expression that contain common factor​
Svet_ta [14]
The common factor would be 3 because 3 is the highest multiple of 15 and 9
6 0
3 years ago
Read 2 more answers
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