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Margaret [11]
3 years ago
6

PLS HELP!!! Help needed immediately!!

Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

Answer:

Step-by-step explanation:

Given Data:

Starting Balance: $100         Annual Rate: 4% = 4/100 = 0.04

Time: 12 years =                      

<em />

<em>The Simple Terms going to be used here:</em>

I:  <em>Amount of money you will make in interest. This shouldn't be confuse with the interest rate, r.</em>  

r: <em>It is the interest rate, And expressed as a percentage. we will always need to convert this number into a decimal by  dividing it by 100. So, for example  5% becomes 0.05.</em>

t:  <em>It is time in terms of years. I-e, a year will become 12 months.</em>

p: <em>It is the principal. That is how much you deposited in the bank or take from it.</em>

<em />

<em>Now Using The formula for the Solution:</em>

<em> </em>I = p * r * t

I = 100*0.04*12

I = $48

Hence The amount left with all the sum will be

A total of: $100 + $48 = $148

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Step-by-step explanation:

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Suppose that the times required for a cable company to fix cable problems in its customers’ homes are uniformly distributed betw
vampirchik [111]

Answer:

a) 60% probability that a randomly selected cable repair visit will take at least 50 minutes

b) 60% probability that a randomly selected cable repair visit will take at most 55 minutes.

c) The expected length of the repair visit is 52.5 minutes.

d) The standard deviation is 7.22 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

For this problem, we have that:

Uniformly distributed between 40 and 65 minutes, so a = 40, b = 65

(a) What is the probability that a randomly selected cable repair visit will take at least 50 minutes?

Either it takes less than 50 minutes, or it takes at least 50 minutes. The sum of the probabilities of these events is decimal 1. So

P(X < 50) + P(X \geq 50) = 1

The intervals can be open or closed, so

P(X < 50) = P(X \leq 50)

We have that

P(X \geq 50) = 1 - P(X < 50)

P(X < x) = \frac{50 - 40}{65 - 40} = 0.4

P(X \geq 50) = 1 - P(X < 50) = 1 - 0.4 = 0.6

60% probability that a randomly selected cable repair visit will take at least 50 minutes

(b) What is the probability that a randomly selected cable repair visit will take at most 55 minutes?

This is P(X \leq 55)

P(X \leq 55) = \frac{55 - 40}{65 - 40} = 0.6

60% probability that a randomly selected cable repair visit will take at most 55 minutes.

(c) What is the expected length of the repair visit?

The mean of the uniform distribution is:

M = \frac{a+b}{2}

So

M = \frac{40+65}{2} = 52.5

The expected length of the repair visit is 52.5 minutes.

(d) What is the standard deviation?

The standard deviation of the uniform distribution is

S = \sqrt{\frac{(b-a)^{2}}{12}}

So

S = \sqrt{\frac{(65-40)^{2}}{12}}

S = 7.22

The standard deviation is 7.22 minutes.

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Answer:

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relative maximum: (-2,80)

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