By De Moivre's formula, the <em>cubic</em> roots of the <em>complex</em> number are 3 + i 4, - 4.96 + i 0.60 and 1.96 - i 4.60.
<h3>How to find the cube root of a complex number</h3>
Herein we have a <em>complex</em> number in <em>rectangular</em> form, from which we need its magnitude (r) and direction (θ) and the De Moivre's formula as well. The <em>root</em> formula is introduced below:
, for k ∈ {0, 1, ..., n - 1} (1)
Where n is the grade of the complex root.
The magnitude and direction of the <em>complex</em> number are 125 and 0.886π radians, respectively. Thus, by the De Moivre's formula we obtain the following three solutions:
k = 0
z₁ = 2.997 + i 4.002
k = 1
z₂ = - 4.964 + i 0.595
k = 2
z₃ = 1.967 - i 4.597
By De Moivre's formula, the <em>cubic</em> roots of the <em>complex</em> number are 3 + i 4, - 4.96 + i 0.60 and 1.96 - i 4.60.
To learn more on complex numbers: brainly.com/question/10251853
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Answer:
Step-by-step explanation:
I'm not sure if I understood what the problem is asking for and if the numbers behind 3 are answer choices but the answer would be 21.
3's times table:
Since 3 times 7 equals 21 the following equations involving division with the numbers 3, 7, and 21 would be:
Hope this helps
Answer:grader
Step-by-step explanation: