Answer:
We can not solve for a unique cost for each soldier.
Step-by-step explanation:
Let x be the daily cost for legionaries and y be the daily cost for archers.
Upon using our given information we will get a system of linear equations as:
Now we will solve for x from our 2nd equation,
Now we will substitute this value in our 1st equation.
We can see that -3y cancels out with 3y and 9 is not equal to 10. So this is an unsolvable system. Therefore, we can not find a unique cost for each soldier.
So when you add mixed numbers, you must convert it into fractions. The four would become part of the fraction and be 43/10 and the six becomes part of the fraction which is 69/10. You can find this by multiplying 4 by the denominator and then adding it to the numerator (4 Times 10 = 40 + 3 = 43/10) and same for the other one. The answer is 112/10, simplify to 11 1/5.
Answer:
what is the question
Step-by-step explanation:
i cant see any question marks
Answer:
A. x=2, y = 7.
B. (2, 7).
Step-by-step explanation:
A. You can eliminate y by subtracting the equations:
y = 8x - 9
y = 4x - 1 Subtract:
0 = 4x - 8
4x = 8
x = 8/4 = 2.
Now substitute for x in the first equation:
y = 8(2) - 9 = 7.
Check in the second equation:
y = 4x - 1
7 = 4(2) - 1 = 7. Check is OK.
B. On the graph they will intersect at the point (2, 7).
They will intersect here because the values x=2 and y=7 satisfy both the 2 equations.
