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s2008m [1.1K]
2 years ago
7

Which of the following is the equation for wave speed?

Chemistry
1 answer:
mamaluj [8]2 years ago
6 0

Answer:

b

Explanation:

b is the answer to your question

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In the figure below, two nonpolar molecules are interacting.Which interaction would most likely cause these molecules to repel e
Fed [463]
Two non-polar molecules are most likely to interact by
induced dipole-induced dipole interaction.

Non-polar substances do not have a permanently established charge distribution due to similar electron affinities of the atoms that are present. Moreover, due to the absence of a polar hydrogen, they cannot exhibit hydrogen bonding. They interact with one another by induced dipole-induced dipole interactions which arise from the molecules of the substances coming into close vicinity of one another.
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3 years ago
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When 0.875 g. of magnesium was heated in air, 1.25 g. of magnesium oxide
Ilia_Sergeevich [38]

Answer:

1. What is the coefficient for calcium in the balanced equation?

2 Ca + 5 NaOH → 4 Na + 2 Ca(OH)2

2. The burning of 20.0 g of acetylene (C2H2) produces what mass of carbon dioxide? You must

write the equation, balance it and solve the mass-mass problem.

a. Balanced equation:

2 C2H2 + 5 O2  4 CO2 + 2 H2O

Explanation:

3 0
3 years ago
PLEASE HELP PICTURE BELOW
seraphim [82]

Answer:

A.      

sorry if  it's wrong

Explanation:

8 0
3 years ago
When an acid reacts with a strong base which product always forms
patriot [66]

Answer:طيزي

Explanation:

4 0
3 years ago
6) A volume of 473 mL of oxygen was collected at 27°C. What volume would the oxygen occupy at
sertanlavr [38]

Answer : The volume of oxygen occupy at 173° would be, 703.2 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=473mL\\T_1=27^oC=(27+273)K=300K\\V_2=?\\T_2=173^oC=(173+273)K=446K

Now put all the given values in above equation, we get:

\frac{473mL}{300K}=\frac{V_2}{446K}\\\\V_2=703.2mL

Therefore, the volume of oxygen occupy at 173° would be, 703.2 mL

6 0
3 years ago
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