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Anarel [89]
3 years ago
15

What percentage of the heat lost by the hot object(s) was gained by the water? Explain at least three factors that might have ca

used the results of parts D and E to be different.
Chemistry
1 answer:
amid [387]3 years ago
6 0

sorry I don't know just kidding I know just kidding I don't know

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What is the pOH of a solution that has an H+=7.7x10^-7 M
pentagon [3]

Answer:

Explanation:

Step 1

The question is based on the concept of PH and pOH calculations.

pH is defined as negative logarithmic of hydronium Ion concentration.

while pOH is defined as negative logarithmic of hydroxide ion concentration of the solution.

Step 2

[H+] = 7.7*10-7  M  

pH = -log[H+]  

    = -log ( 7.7*10-7 )

     = 6.12

Step 3

pOH = 14 - pH

   = 14 - 6.11

  = 7.89

4 0
3 years ago
What is the correct name of CUCIO2<br> Chemistry
Deffense [45]

Answer:

Copper(II) Chlorite = Cu(ClO2)

Explanation:

how you write the compound is very important as well

5 0
3 years ago
Which number is 0.0069 expressed in scientific notation?
natali 33 [55]
6.9 x 10 to the power of 3 if I am not mistaken.
7 0
3 years ago
Read 2 more answers
HELP ME ASAP!
guajiro [1.7K]
Hope this helps

Answer: Families move away from shorelines.
8 0
3 years ago
How many kilograms of a fertilizer are made of pure P2O5 would be required to supply 1.69 kilogram of phosphorus to the soil?
Alekssandra [29.7K]

Answer:

3.89 kg P2O5 must be used to supply 1.69 kg Phosphorus to the soil.

Explanation:

The molecular mass of P2O5 is

P2 = 2* 31 =           62

O5 = 5 *<u> 16 =         80</u>

Molecular Mass = 142

Set up a Proportion

142 grams P2O5 supplies 62 grams of phosphorus

x    kg P2O5        supplies 1.69 kg of phosphorus

Though this might be a bit anti intuitive, you don't have to convert the units for this question. The ratio is all that is important.

142/x = 62/1.69            Cross multiply

142 * 1.69 = 62x           combine the left

239.98 = 62x               Divide by 62

239.98/62 = x

3.89 kg of P2O5 must be used.

3 0
3 years ago
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