Answer:
thethe answer is the 3rd one
This is true. The numbers being arranged differently in this does not mean it'll not equal each other.
Answer:
1. I dont know what format they want you to write it in but its 27/100 which is 0.27 as a decimal and 27% as a percent
2. it'll be 11/100 which is 0.11 as a decimal and 11% as a percent
Step-by-step explanation:
Since adding up all the people with cats, dogs or both is 73, and theres 100 people surveyed, that means 100-73=27 so 27 people dont have a cat or dog. Therefore its 27/100 which is 0.27 as a decimal and 27% as a percent
For number 2, because 11 people have both a dog and cat I believe itll be 11/100 which is 0.11 as a decimal and 11% as a percent
Answer:
P = 0,0012 or P = 0.12 %
Step-by-step explanation:
We know for normal distribution that:
μ ± σ in that range we find 68.3 % of all values
μ ± 2σ ⇒ 95.5 % and
μ ± 3σ ⇒ 99.7 %
Fom problem statement
We have to find (approximately) % of cars that reamain in service between 71 and 83 months
65 + 6 = 71 ( μ + σ ) therefore 95.5 % of values are from 59 and up to 71 then by symmetry 95.5/2 = 49.75 of values will be above mean
Probability between 65 and 71 is 49.75 %
On the other hand 74 is a value for mean plus 1, 5 σ and
74 is the value limit for mean plus 1,5 σ and correspond to 49,85 (from z=0 or mean 65).
Then the pobabilty for 83 have to be bigger than 49.85 and smaller than 0,5 assume is 49.87
Finally the probability approximately for cars that remain in service between 71 and 83 months is : 0,4987 - 0.49.75
P = 0,0012 or P = 0.12 %
<em>1/6 = 0.16 acres in 8 minutes. </em>
<em>--</em>
<em>0.16 ÷ 8 = 0.02 acres mowed in 1 minute.</em>
<em>--</em>
<em>(60 minutes in an hour)</em>
<em>0.02 x 60 = 1.2 acres mowed in an hour.</em>
<em>-- </em>
<em>1.2 is equal to 1 1/5, and jami needs to mow 1 1/2 acres.</em><em> so no, jami cannot mow 1 1/2 acres in an hour.</em>
