Answer:
17
(
2
x
+
1
)
Step-by-step explanation:
Factor the polynomial.
I don’t think you can do that
Answer:
x = 10°
Step-by-step explanation:
The diagonals of a rhombus divide the figure into congruent right triangles. That means the two marked acute angles are complementary.
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<h3>solve for x</h3>
Complementary angles total 90°, so the relation we can use to find x is ...
(3x -13) +(8x -7) = 90
11x = 110 . . . . . . . . . add 20
x = 10 . . . . . . . . . divide by the coefficient of x
The value of x is 10°.
The answer for that problem is z =12+6
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
