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tatiyna
3 years ago
12

MyProgramming Lab

Computers and Technology
1 answer:
AleksAgata [21]3 years ago
4 0

Answer:

The program in Python is as follows:

#1

d = int(input("distance: "))

n = int(input("n: "))

arith_prog = []

for i in range(1,n+1,d):

   arith_prog.append(i)

print(arith_prog)

#2

d = int(input("distance: "))

m = int(input("m: "))

n = int(input("n: "))

arith_prog = []

for i in range(m,n+1,d):

   arith_prog.append(i)

print(arith_prog)

#3

r = int(input("ratio: "))

n = int(input("n: "))

geom_prog = []

m = 1

count = 0

while(m<n):

   m = r**count

   geom_prog.append(m)

   count+=1

print(geom_prog)

Explanation:

#Program 1 begins here

This gets input for distance

d = int(input("distance: "))

This gets input for n

n = int(input("n: "))

This initializes the list, arith_prog

arith_prog = []

This iterates from 1 to n (inclusive) with an increment of d

for i in range(1,n+1,d):

This appends the elements of the progression to the list

   arith_prog.append(i)

This prints the list

print(arith_prog)

#Program 2 begins here

This gets input for distance

d = int(input("distance: "))

This gets input for m

m = int(input("m: "))

This gets input for n

n = int(input("n: "))

This initializes the list, arith_prog

arith_prog = []

This iterates from m to n (inclusive) with an increment of d

for i in range(m,n+1,d):

This appends the elements of the progression to the list

   arith_prog.append(i)

This prints the list

print(arith_prog)

#Program 3 begins here

This gets input for ratio

r = int(input("ratio: "))

This gets input for n

n = int(input("n: "))

This initializes the list, geom_prog

geom_prog = []

This initializes the element of the progression to 1

m = 1

Initialize count to 0

count = 0

This is repeated until the progression element is n

while(m<n):

Generate progression element

   m = r**count

Append element to list

   geom_prog.append(m)

Increase count by 1

   count+=1

This prints the list

print(geom_prog)

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Answer:

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          while (lineScanner.hasNext()) {

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                  } else if (ind2 == 11) {

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      }

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}

Explanation:

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Answer:

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