We suppose that every one paid $10 for entrance. So the total paid should be $1000. Now there is $300 more. The faculty should pay $15 more than student. So the faculty number is $300/15=20. Then the number of student is 80.
Answer:
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Radius = d/2 = 1.7 in
circumference = πd ≈ 3.14*3.4 in = 10.68 in
Solution:
we are given that
John is 3 years older than Jim. Jim is 4 years less than half of Dana’s age.
Let the age of Jim be x years then we can say
Age of John
If diana Age is D then
It can be re-wriiten as
Diana age 
Given that their ages add up to 167
Hence jim is 39 nyears old, John is 39+3=42 years old. and Diana is 2*39+8=78+8=86 years old.
Answer:
a) 658008 samples
b) 274050 samples
c) 515502 samples
Step-by-step explanation:
a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.
So, the number of samples = ⁴⁰C₅ = 658008 samples
b) How many samples of 5 contain exactly one nonconforming chip?
There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways
¹⁰C₁ = 10 ways
then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways
³⁰C₄ = 27405 ways
So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples
c) How many samples of 5 contain at least one nonconforming chip?
The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)
Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples
Total number of samples = 658008
The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples
