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uranmaximum [27]
3 years ago
14

4x-3y=6 4x+y=14 type a ordered pair

Mathematics
1 answer:
podryga [215]3 years ago
5 0

Answer:

(3,2)

Step-by-step explanation:

If you graph the equations, they cross at this point.

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Write the product, and then write the expression in standard form by removing parentheses and combining like terms.
Nina [5.8K]

Step-by-step explanation:

please see it my steps to work this problem

6 0
3 years ago
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Solve the equation, and check the solution. w/3 = 0.9 (The w is a variable for the fraction)
zheka24 [161]

Answer:

w = 2.7

Step-by-step explanation:

To solve for what number divided by 3 is equal to 0.9 you can do 0.9*3 and get the answer 2.7. w = 2.7.

3 0
3 years ago
In which two midwestern states are there cattle ranches
Svetradugi [14.3K]

Answer:

Minnesota and Iowa

Step-by-step explanation:

5 0
4 years ago
A box contains three cards. On one card there is a question mark ​(Upper Q​), on another card there is a pear ​(Upper P​), and o
vova2212 [387]

Complete question :

Determine the probability that two pears are selected The probability is(Simplity your answer.)

d) Determine the probability that a card containing a PEAR and then a card containing a question mark are selected

Answer:

(QQ, QP, QM, QP, PP, MP, QM, PM, MM) ;

Step-by-step explanation:

Given :

Marking on card :

Question mark = Q

Pear = P

Moon = M

Selecting two cards with replacement :

Sample space :

_____ Q ____ P _____ M

Q ___QQ ___QP ___ QM

P ___QP ____PP ___ MP

M__ QM ____PM ___MM

(QQ, QP, QM, QP, PP, MP, QM, PM, MM) ;

1/9 ;

2/9

P(selecting 2 pears) = (PP)

P(p) = required outcome / Total possible outcomes = 1 / 9

Card containing a pear and then a question mark ;

(PQ or QP).

P(p) = 1/3 ; P(Q) = 1/3

P(PQ) + P(QP)

(1/3 * 1/3) + (/3 * 1/3)

1/9 + 1/9

(1 + 1) / 9

= 2/9

6 0
3 years ago
What’s the answer? All answers please
Doss [256]

Answer:

11. no solution

12. 12, -12.

13. 4/3, -4/3.

14. 6/5, -6/5.

15. 1/2, -1/2.

16. 7/4, -7/4.

Step-by-step explanation:

11. Why it is no solution is when you minus 66 from 3 you get a -63. You then divide 7 by that to get -9. Every time you put a negative inside a square root it will equal no solution every time.

12. 1/2x^2+3=75. I minused the 3 from both sides.

1/2x^2=72. I then times 1/2 to both sides to get 144.

x^2=144. I then square rooted both sides to get 12, -12.

13. 9x^2-16=0. I added 16 to both sides.

9x^2=16. I then divided 9 to both sides.

x^2=16/9. I then square rooted both sides to get 4/3, -4/3.

14. 25x^2+10=46. I minused the 10 from both sides.

25^2=36. I then divided 25 from both sides.

x^2=36/25. I then square rooted both sides to get 6/5, -6/5.

15. 5x^2-1=x^2. I minused x^2 from both sides.

4x^2-1=0. I added 1 to both sides.

4x^2=1. I divided 4 to both sides.

x^2=1/4. I square rooted both sides to get 1/2, -1/2.

16. 16x^2-34=15. I added 34 to both sides.

16x^2=49. I divided 16 to both sides.

x^2=49/16. I square rooted both sides to get 7/4, -7/4.

If you plug those answers into the equations. It should equal what it is equal to.  

3 0
3 years ago
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