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3 years ago

What is the electronegativity difference for a bond between potassium and iodine? A. 3.3 B. 4.6 C. 0.4 D. 1.7

Chemistry

2 answers:

Elis [28]3 years ago

8 0

Answer is: D. 1.7.

Electronegativity (χ) is a property that describes the tendency of an atom to attract a shared pair of electrons. Atoms with higher electronegativity attracts more electrons towards it, electrons are closer to that atom.

When the electronegativity difference is greater, the bond polarity is increasing.

Δχ(K-I) = 2.5 - 0.8.

Δχ(K-I) = 1.7; the electronegativity difference for a bond between potassium and iodine.

user100 [1]3 years ago

7 0

Iodine has an electronegativity of 2.5, and potassium has an electronegativity of 0.8, so the difference is:
2.5 - 0.8 = 1.7

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Explanation:

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Kb = 1.8x10⁻⁵ = [NH₄⁺] [OH⁻] / [NH₃]

<em>As all NH₄⁺ and OH⁻ comes from the same source we can write: </em>

<em>And as </em>[NH₃] = 0.619M

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What is the pOH of a 0.150 M solution of potassium nitrite? (Ka HNO2 = 4.5 x 10−4 )

yanalaym [24]

Answer:

11.9 is the pOH of a 0.150 M solution of potassium nitrite.

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Solution : Given,

Concentration (c) = 0.150 M

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First we have to calculate the concentration of value of dissociation constant $(\alpha )$ .

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Now put all the given values in this formula ,we get the value of dissociation constant $(\alpha )$ .

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$4.5\times 10^{-4} - 4.5\times 10^{-4}\alpha =0.150\alpha ^2$

$0.150\alpha ^2+4.5\times 10^{-4}\alpha-4.5\times 10^{-4}=0$

By solving the terms, we get

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Now we have to calculate the pH.

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