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3 years ago

Compare gases with liquids and solids according to the kinetic molecular theory

2 answers:

8 0

Solids have molecules that are held tightly together in close bonds. (positive bonded to a negative) They can bend or vibrate but still stay bonded together closely. Solids have very little kinetic energy. 

Liquids have molecules that are held in looser bonds. They move more freely and more randomly that in a solid. It is common for the bonds to be flexible enough to slide over each other. 

Gasses have the loosest bond of any state of matter. The loose bonds allow the molecules to move freely and far apart. A gas has the greatest kinetic energy of any state of matter,

Alexxx [7]3 years ago

6 0

Solids molecules are tightly held together in close bonds,they could bend or vibrate but still stay bonded. So they have little k.e Liquid molecules are much loser than solid,its bond are flexible enough to slide over eachother. So it has greater k.e compared to solid Gas molecules are the most loosed,they take the shape of the container thus its molecules moves freely colliding btw themselves and its container. So gas has the greatest k.e amongs the rest

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At 25°C, the equilibrium constant Kc for the reaction in thesolvent CCl4 2BrCl <----> Br2 + Cl2 is 0.141. If the initial c

ivolga24 [154]

Answer: The equilibrium concentration of bromine gas is 0.00135 M

Explanation:

We are given:

Initial concentration of chlorine gas = 0.0300 M

Initial concentration of bromine monochlorine = 0.0200 M

For the given chemical equation:

$2BrCl\rightleftharpoons Br_2+Cl_2$

Initial: 0.02 0.03

At eqllm: 0.02-2x x 0.03+x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[Br_2]\times [Cl_2]}{[BrCl]^2}$

We are given:

$K_c=0.141$

Putting values in above equation, we get:

$0.141=\frac{x\times (0.03+x)}{(0.02-2x)^2}\\\\x=-0.96,+0.00135$

Neglecting the value of x = -0.96 because, concentration cannot be negative

So, equilibrium concentration of bromine gas = x = 0.00135 M

Hence, the equilibrium concentration of bromine gas is 0.00135 M

8 0

3 years ago

What is another name for the Group 2 Elements? *

Ira Lisetskai [31]

Group 2 elements are the alkaline earth metals

5 0

2 years ago

C12H22011+1202-->12CO2+11H20

kogti [31]

Answer:

0.185moles

Explanation:

Given parameters:

Volume of O₂ = 49.8L

Unknown:

Number of moles of sucrose required = ?

Solution:

We can assume that the reaction takes place at standard temperature and pressure.

From this, we can find the number of moles of oxygen that reacted and extrapolate to that of sucrose.

Chemical equation;

C₁₂H₂₂0₁₁ + 120₂ → 12CO₂ + 11H₂0

Number moles = $\frac{volume of gas}{22.4}$ at STP

Number of moles of oxygen gas = $\frac{49.8}{22.4}$ = 2.22moles

12 moles of oxygen gas combines with 1 mole of sucrose

2.22 moles of oxygen gas will combine with $\frac{2.22}{12}$ = 0.185moles

4 0

3 years ago

(select all that apply.) the elements most often found in organic molecules are _____.

Arturiano [62]

C. Carbon. H. Hydrogen. N. Nitrogen. O. Oxygen. P. Phosphorus. S. Sulfur.

7 0

3 years ago

Read 2 more answers

What is the Ka of a weak acid (HA) if the initial concentration of weak acid is 4.5 x 10-4 M and the pH is 6.87? (pick one)

rewona [7]

Answer:

Ka = $4.04 \times 10^{-11}$

Explanation:

Initial concentration of weak acid = $4.5 \times 10^{-4}\ M$

pH = 6.87

$pH = -log[H^+]$

$[H^+]=10^{-pH}$

$[H^+]=10^{-6.87}=1.35 \times 10^{-7}\ M$

HA dissociated as:

$HA \leftrightharpoons H^+ + A^{-}$

(0.00045 - x) x x

[HA] at equilibrium = (0.00045 - x) M

x = $1.35 \times 10^{-7}\ M$

$Ka = \frac{[H^+][A^{-}]}{[HA]}$

$Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 - 0.000000135}$

0.000000135 <<< 0.00045

$Therefore, Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 } = 4.04 \times 10^{-11}$

5 0

3 years ago