16 - 4 [ 3 + 2 / (9 - 7)]
16 - 4 [ 3 + 2 / 2)]
16 - 4 [ 3 + 1 ]
16 - 4 [4]
16 - 16
0 <===
Answer:
They are b and c.
Step-by-step explanation:
Let's simplify each expression:
a. b+2 (b+2b)
= b + 2b + 4b = 7b.
b. 3b + b = 4b.
c. 2(2b) = 2 * 2b = 4b.
Answer:

Step-by-step explanation:
Given

Required
Approximate (to the nearest 100th)
This means that, we approximate at the second digit after the decimal.
So:
i.e,
Number = 39.79 [Begin approximation] 949748
The first digit after [Begin approximation] is then approximated using the following rule:


Since 9 falls in
category, the number becomes:
![Number = 39.[79+1]](https://tex.z-dn.net/?f=Number%20%3D%2039.%5B79%2B1%5D)

The anser would be 500 with the exponet of 100 solve my multiplying
Answer:
$12.80
Step-by-step explanation:
Before markup: $8
After markup: $8 x 160% = $12.80
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