Answer:
the ion present in the original solution is Ca2+
Explanation:
Precipitation reactions occur when cations and anions in aqueous solution combine to form an insoluble ionic solid called a precipitate.
<u>Step1</u> : If we add Nacl to the solution, there is no precipitate formed
⇒The only possible ion that can form a precipate with Cl- is Ag+; since there is no precipitate formed, Ag+ is not present
<u>Step2</u> : If we add Na2SO4 to the solution, a white precipitate is formed
The possible ions to bind at SO42- are Ca2+ and Fe2+
But the white precipitate formed, points in the direction of Ca2+
⇒This means calcium is present
<u>Step3</u> : If we add Na2CO3 to the filtered solution, there is a precipate formed
Ca2+ will bind also with CO32- and form a precipitate
So the ion present in the original solution is Ca2+
Answer is: d) Hg.
Mercury is a chemical element with the symbol Hg and atomic number 80. <span> Mercury is the only metallic element that is liquid at standard conditions for temperature and pressure.
</span>Absolute viscosity of mercury is 0,0015 Pa·s.
The viscosity<span> of a </span>fluid<span> is a measure of its </span>resistance<span> to gradual deformation by </span>shear stress<span> or </span><span>tensile stress</span>
If an electron absorbs enough energy it would jump to a higher energy level.
Answer:
C. 3.74 g/L
Explanation:
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Also,
Moles = mass (m) / Molar mass (M)
Density (d) = Mass (m) / Volume (V)
So, the ideal gas equation can be written as:
At STP,
Pressure = 1 atm
Temperature = 273.15 K
Molar mass of krypton gas = 83.8 g/mol
Applying the equation as:
1 atm × 83.8 g/mol = d × 0.0821 L.atm/K.mol × 273.15 K
⇒d = 3.74 g/L
Elements with similar properties are aligned vertically. The family is called groups.
