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Alexandra [31]
3 years ago
14

Bohr recognized that the electrons in the shells surrounding the nucleus were able to move to different energy levels. if an ele

ctron ________ enough energy it would jump to a higher energy level.
Chemistry
2 answers:
Ksenya-84 [330]3 years ago
7 0

Answer: absorbs

Explanation:

Bohr in his structure of atom explained that electrons revolve around the nucleus in fixed orbit or shell or energy levels.These energy levels are stable and are stationary along with different energy value.

A electron can jump to higher energy levels on absorbing the enough energy required to do so.

The electron in higher energy level is unstable and thus gets back to its original state by emitting the energy absorbed.

Thus electron would jump to a higher energy level when it absorbs enough energy.

Over [174]3 years ago
4 0
If an electron absorbs enough energy it would jump to a higher energy level.
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Explain the difference in the boiling point of 2-methylpropane and 2-iodo-2-methylpropane in terms of both molecular polarity an
Len [333]
The Boiling Point of 2-methylpropane is approximately -11.7 °C, while, Boiling Point of <span>2-iodo-2-methylpropane is approximately 100 </span>°C.

As both compounds are Non-polar in nature, So there will be no dipole-dipole interactions between the molecules of said compounds.

The Interactions found in these compounds are London Dispersion Forces.

And among several factors at which London Dispersion Forces depends, one is the size of molecule.

Size of Molecule:
                          There is direct relation between size of molecule and London Dispersion forces. So, 2-iodo-2-methylpropane containing large atom (i.e. Iodine) experience greater interactions. So, due to greater interactions 2-iodo-2-methylpropane need more energy to separate from its partner molecules, Hence, high temperature is required to boil them.
6 0
3 years ago
Is it possible for the equivalence point of a titration to not be at pH 7? Explain your answer.
lara31 [8.8K]
<span>The reason it will be 7 for some titrations is that when you  titrates a strong acid with a strong base for example  HCl and NaOH the salt formed is conjugate base of strong acid and will be a very weak base
 That means that it cannot produce any OH^-1 and all the H+ has been converted to water.The only source of H+ or OH is water with a Ka of 10^-14 so the pH = -log [H+]=-log 10^-7 = 7 
second reason is 
When you titrates a weak acid with strong base at equivalence point 
only a water solution of the conjugate base exists 

CH3COOH + NaOH ----- Na+ CH3COO^-1 + H2O 
Since the conjugate base is the conjugate base of a weak acid it will hydrolyze in water like so 
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hope this helps</span>
5 0
3 years ago
Read 2 more answers
Hi! I'm on the last question of my homework and I'm stuck on it and was wondering if anyone could help me
Semmy [17]
I am not sure but this is what I think

This question uses the formula connecting mass, density and volume
Which is Density= Mass/Volume

Convert the mass in g
92.5 kg = 92,500g


7.87g/ml = 92,500/ Volume
Volume= 92,500/7.87
= 11,753.5 ml

Now since we have to give the answer in liters we can just divide by 1000 and get
11.75 litres

5 0
2 years ago
3. When two atoms bond together to form a molecule, which parts of the atoms
fenix001 [56]

Answer:

Atoms come together to form molecules because of their electrons. Electrons can join (or bond) atoms together in two main ways. When two atoms share electrons between them, they are locked together (bonded) by that sharing. These are called covalent bonds

5 0
3 years ago
Compound a has a pka of 7 and compound b has a pka of 10. compound a is how many times more acidic than compound b?
Pavel [41]
Ka is the acid dissociation equilibrium constant. The larger the value of the Ka, the stronger is the acid. To find Ka from pKa, the equation is:

pKa = -log[Ka]

@pKa = 7
7 = -log[Ka]
Ka = 1×10⁻⁷

@pKa = 10
10 = -log[Ka]
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This, pKa 7 is more acidic than pKa 10. The scale factor would be:
1×10⁻⁷/1×10⁻¹⁰ = 1,000

<em>Therefore, Compound A is 1,000 times more acidic than Compound B.</em>

4 0
3 years ago
Read 2 more answers
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