According to Lavoisier's law, in the given reaction the mass of zinc produced will be 104 g.
Let's consider the following reaction.
Ca + ZnCO₃ ⇒ CaCO₃ + Zn
64g 192 g 152 g ? g
<h3>What does Lavoisier's law state?</h3>
Lavoisier's law states that the sum of the masses of the reactants before the reaction is equal to the sum of the masses of the products after the reaction.
mCa + mZnCO₃ = mCaCO₃ + mZn
mZn = mCa + mZnCO₃ - mCaCO₃
mZn = 64 g + 192 g - 152 g = 104 g
What would be the amount of zinc formed during the reaction?
- The mass of zinc produced will be 104 g. TRUE.
- The mass of zinc will be the same as that of zinc carbonate. FALSE.
- The mass of zinc produced will be 52 g. FALSE.
- The mass of zinc will be the same as that of calcium. FALSE.
According to Lavoisier's law, in the given reaction the mass of zinc produced will be 104 g.
Learn more about Lavoisier's law here: brainly.com/question/11429078
Answer:
contractile vacuole
Explanation:
contractile vacuole is used for balance of water,salt etc
Answer:
Explanation:
We are asked to find how much of a 40 gram sample remains after 12 years.
Iron-55 has a half-life of 3 years. Therefore, after 12 years, 4 half-lives have been completed.
- 12 years/3 years = 4 half-lives
Every time a half-life is completed, half of the sample's mass decays. Remember we start with a 40 gram sample.
- 1 half- life: 40 g / 2 = 20 g
- 2 half-lives: 20 g / 2= 10 g
- 3 half-lives: 10 g / 2 = 5 g
- 4 half-lives: 5 g / 2 = 2.5 g
There is also a formula that can be used to solve this problem.
Where A₀ is the initial amount, t is the time, and hl is the half-life.
We know 40 grams is the inital amount, 12 years is the time, and 3 years is the halflife.
After 12 years, <u>2.5 grams </u> of Iron-55 will remain.
They run up a tree and steal them from all the birds nests then swallow them
