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gregori [183]
3 years ago
9

Select the correct answer​

Mathematics
2 answers:
Valentin [98]3 years ago
7 0

Answer:

c

Step-by-step explanation:

lyudmila [28]3 years ago
4 0

Answer:

Cos P

Step-by-step explanation:

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Help please ASAP thx all of them
Radda [10]
Hi, these equations are pretty easy actually, first thing you should know when working with variables is that you always want to leave the variable alone, let's take the third excersise for example, 12x + 2 = 146. Here you just do the opposite on the other side of the equation depending if the number is positive or negative. Since x is being multiplied by 12 you first get rid of the 2, since its positive you subtract it to 146. Now the answer should be 12x = 144. Now since you're multiplying 12 to x you just divide 12 from 144, 144/12 = 12
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3 years ago
How do you write 77/20 in a decimal
Sveta_85 [38]
Writing it as a decimal would be 3.85 you just divide it
7 0
3 years ago
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the perimeter of a rectangular field is 374 yards. if the width of the field is 88 yards, what is its length
aksik [14]

Answer:

99 yards

Step-by-step explanation:

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3 0
3 years ago
Danielle plans on making monthly payments into an account that earns 2.5% compounded monthly. If she wants $10,000 in 22 years,
Nesterboy [21]

Answer:

5,500

Step-by-step explanation:

I=PRT/100

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4 0
3 years ago
A Pentagon is transformed according to the rule R0, 180°. Which is another way to state the transformation?
postnew [5]

The another way to state the transformation would be (x,y)>(-x,-y)

<u>Solution:</u>

Rotation about the origin at 180^\circ: R_{180^\circ}A \rightarrow O = R_{180^\circ} (x, y) \rightarrow (-x,-y)

The term R0 means that the rotation is about the origin point. Therefore, (R0,180) means that we are rotating the figure to 180^\circ about the origin.

So, the transformation of the general point (x,y) would be (-x,-y) when it is rotated about the origin by an angle of 180^\circ.

Hence according to the representation, the expression would be (x, y) \rightarrow (-x, -y).

8 0
3 years ago
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