Well do 24 - 13.
You should get 11.
N = 11.
Answer:
part 1 : y = x^2 + 3x + 5
y = x + 13
solution:
x^2 + 3x + 5 = x + 13
x^2 + 2x -8 = 0
(x+4)(x-2) = 0
x = -4 or x = 2
if x = -4, y = 9
if x = 2 , y = 15
part 2 : x^2 + 2x + 1 = 0
(x + 1)^2 = 0
x = -1
y = 1
task 2
part 1 : Let our two digit number be 26
Next, we rewrite it as a difference of two numbers
26=32-6
We want to square 26 using the identity:
In this case,
x=32
y=6
Substituting into the identity
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Answer:
10
Step-by-step explanation:
because your more likely to open to a page deeper in the magazine
Let the numbers be x and y.
x*y=HCF*LCM=6*60=360
thus
y=360/x
next we find the list of combinations of x and y and test if they satisfy the conditions above:
(6,60),(12,30),(18,20),(24,15)
out of the above, only (6,60) and (12,30) satisfy both conditions. Thus our answer is:
(6,60) or (12,30)
Answer:
x = 13
Step-by-step explanation:
call the missing number x
8 - x = - 5 Subtract 8 from both sides
8-8 - x = -5-8 Combine
-x = - 13 Multiply by -1
x = 13
