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3 years ago

Gustavo is the league's home run leader. The probabilities for his total number of home runs for the season are as follows:

Mathematics

1 answer:

Ugo [173]3 years ago

4 0

Answer:

dont copy and paste i cant read the question

Step-by-step explanation:

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WILL GIVE BRAINLIEST 27 points

tangare [24]

It is not direct variation because it does not follow the equation
y = slopex
THE points do not make the equation true .

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3 years ago

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Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer

lyudmila [28]

$f(\theta)=10\cos\theta+5\sin^2\theta$

then the derivative is

$f'(\theta)=-10\sin\theta+10\sin\theta\cos\theta$

Critical points occur where $f'(\theta)=0$ . This happens for

$-10\sin\theta+10\sin\theta\cos\theta=0$

$-10\sin\theta(1-\cos\theta)=0$

$\implies-10\sin\theta=0\text{ or }1-\cos\theta=0$

In the first case, we find

$-10\sin\theta=0\implies\sin\theta=0\implies\theta=n\pi$

In the second,

$1-\cos\theta=0\implies\cos\theta=1\implies\theta=2n\pi$

So all the critical points occur at multiples of $\pi$ , or $n\pi$ . (This includes all the even multiples of $\pi$ .)

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3 years ago

Which is a y-intercept of the graphed function? (–9, 0) (–3, 0) (0, –9) (0, –3)

Inessa05 [86]

Answer:

The y-intercept of the graphed function is (0,-9)

Step-by-step explanation:

The y-intercept of the graphed function is (0,-9) because the y-intercept is where the point where the line meets with the y-axis, and the point where the line meets with the y axis is (0,-9)

Therefore the answer is

(0,-9)

I hope this helped you.

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3 years ago

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What is the missing coefficient?

Kryger [21]

Answer:

Since 15-7=8, answer is 8.

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3 years ago

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. Find the probability

yawa3891 [41]

Complete Question

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Find the probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

Answer:

0.9875

Step-by-step explanation:

Total Number of Guests which forms the Sample Space, n(S)=80

Let the Event (a friend of the bride) =A

Let the Event (a friend of the groom) =B

n(A) =59

n(B)=50

Friends of both bride and groom, $n(A \cap B)=30$

Therefore:

$n(A \cup B)=n(A)+n(B)-n(A \cap B)\\n(A \cup B)=59+50-30\\n(A \cup B)=79$

The number of Guests who was a friend of the bride OR of the groom = 79

Therefore:

The probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

$P(A \cup B) =\dfrac{n(A \cup B) }{n(S)} \\\\=\dfrac{79 }{80}\\\\=0.9875$

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3 years ago