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3 years ago

PLZ HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Jlenok [28]3 years ago

7 0

Answer:

Step-by-step explanation:

Andreyy893 years ago

5 0

Answer:

Step-by-step explanation:

9 * 9 * h = 1620. Isolate the variable. h = 20. The equation would be 9*9*20 or 9^2*20.

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Please help<br> 1. f(x)=3(2)^x<br> 2. f(x)=2(3)^x<br> 3. f(x)=3(1/2)^x<br> 4. f(x)=2(1/3)^x

stellarik [79]

Answer:

C. f(x)=3(1/2)^x

Step-by-step explanation:

standard form of a function is f(x)=ab^x

a should be 3, or the y value where the x value is 0

the b value is 1/2 because that's the rate of change

8 0

3 years ago

Trapezoid WKRP was translated 4 units to the left and 5 units up on a coordinate grid to create trapezoid W’K’R’P’. Which rule d

saw5 [17]

The rule used to describe this transformation is (x, y)→(x - 4, y + 5)

<h3>Transformation</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are<em> rotation, reflection, translation and dilation.</em>

If a point A(x, y) is translated a units left and b units up. the new point is at A'(x - a, y + b)

Given Trapezoid WKRP was translated 4 units to the left and 5 units up on a coordinate grid to create trapezoid W’K’R’P’. The rule is given by:

(x, y)→(x - 4, y + 5)

The rule used to describe this transformation is (x, y)→(x - 4, y + 5)

Find out more on Transformation at: brainly.com/question/1462871

3 0

2 years ago

Write 180 feet per 12 seconds as a unit rate

Ber [7]

15ft per sec would be the unit rate.

7 0

3 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago

Perform the following calculations without rewriting the numbers in decimal form.

Bingel [31]

Answer:

After multiplication number will be $3.408\times \times 10^{28}$

Step-by-step explanation:

We have given numbers which has to multiply using scientific notation

That are $1.42\times 10^{15}\times 2.4\times 10^{13}$

We have to multiply the above number using scientific notation

We know that when two number are multiplied then there exponent power is being added

So when we multiply $1.42\times 10^{15}\times 2.4\times 10^{13}$ there power will be added and after multiplication number will be $3.408\times \times 10^{28}$

6 0

3 years ago