Recall the inverse function theorem: if f(x) has an inverse, and if f(a) = b and a = f⁻¹(b), then
f⁻¹(f(x)) = x ⇒ (f⁻¹)'(f(x)) • f'(x) = 1 ⇒ (f⁻¹)'(f(x)) = 1/f'(x)
⇒ (f⁻¹)'(b) = 1/f'(a)
Let b = 10. Then pick the function f(x) such that f(a) = 10 and f'(a) = -8 for some number a.
9514 1404 393
Answer:
M₅ = 1.6570
Step-by-step explanation:
The basic idea is to find the function values at x ∈ {1.1, 1.3, 1.5, 1.7, 1.9}, add those values, and multiply the result by 1/5. Those x-values are the midpoints of intervals 0.2 units wide, between x = 1 and x = 2. The width 0.2 is the total interval width (2-1=1) divided by n = 5.
The calculation and results are shown in the attachment. Rounded to 4 decimal places, the integral is ...
M₅ = 1.6570
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The actual integral is about 1.6574, so this is pretty close.
Answer:
See below
Step-by-step explanation:
Translation about the y axis would be y = f(-x)
Local max point of G is seen as -3,4 (NOT ASKED FOR)
<u>Local max for -f(x) would be at 3, -4 as the negative sign flips around the x-axis (this would be the max point flipped BUT a MAX point would be 6,0 </u>
1200
you just do 4 multiplied by 6 to get 24 and then multiply 24 by 50 and you have 1200
Answer:
The answer is 66.
Step-by-step explanation:
