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3 years ago

What is the missing length? 18 m and w. Area = 90 m ^2. W =____ meters

Mathematics

1 answer:

7nadin3 [17]3 years ago

7 0

Answer:

10 meters

Step-by-step explanation:

To calculate area of the triangle we multiply height with base and that divided by two

90 = (18 × w) ÷ 2

180 = 18w

w = 10 meters

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iren [92.7K]

Answer:

1/4

Step-by-step explanation:

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3 years ago

Find f (2b^2) for (x)=x^2-4x

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

We are given the function:

$f(x) = x^2 - 4x$

And we want to find:

$\displaystyle f(2b^2)$

Substitute:

$\displaystyle f(2b^2) =(2b^2)^2 -4(2b^2)$

And evaluate:

$\displaystyle \begin{aligned} f(2b^2) &=(2b^2)^2 -4(2b^2) \\ &=(4b^4) +(-8b^2) \\ &= 4b^4 - 8b^2 \end{aligned}$

In conclusion, our answer is A.

7 0

3 years ago

Need help asap please

cupoosta [38]

Answer:

c = 5

Step-by-step explanation:

IT'S THE THREE FOUR FIVE TRIANGLE!!

3^2 + 4^2 = c^2

√25 = c

c = 5

4 0

3 years ago

Read 2 more answers

1.5.PS-21

dybincka [34]

Answer:

Increase in the length of one side = 3.8 ft

Step-by-step explanation:

Yossi has garage whose area is 280 ft²

After rebuilt their is increment in area by 50%

New Area = 280 × 150% = 420 ft²

Also we know that Area of Square = (Length) × (Length)

⇒ Length of Newly built garage = √420 = 20.5 ft

and Length of Originally garage = √280 = 16.7 ft

⇒ Increase in the length of one side = 20.5 - 16.7 = 3.8 ft

6 0

3 years ago

One tank is filling at a rate of 5/8 gallon per 7/10 hour. A second tank is filling at a rate of 5/9 gallon per 2/3 hour. Which

anzhelika [568]

First recognize that the unit rate we're finding is gallons per hour, or $\frac{g}{h}$ .

rate for Tank 1 = x gallons per hour = a gallons / b hours

$T_{1}=\frac{\frac{5}{8}}{\frac{7}{10}}\\\\T_{1}=\frac{5}{8}*\frac{10}{7}\\\\T_{1}=\frac{50}{56}\\\\\\Fill\ rate\ of\ Tank\ 1=\frac{25}{28}$

rate for Tank 2 = y gallons per hour = c gallons / d hours

$T_{2}=\frac{\frac{5}{9}}{\frac{2}{3}}\\\\T_{2}=\frac{5}{9}*\frac{3}{2}\\\\T_{2}=\frac{15}{18}\\\\T_{2}=\frac{15}{18}\\\\\\Fill\ rate\ of\ Tank\ 2=\frac{5}{6}$

3 0

3 years ago