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Soloha48 [4]
2 years ago
13

Is this a function? Yes or no {(2,3), (-3,5),(2,6), (-1,0), (3,7)}

Mathematics
1 answer:
mixas84 [53]2 years ago
5 0

Answer:

no

Step-by-step explanation:

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Answer: forty five and  tfourenths      eight eight and eight hundreths        seventeen hundreths     two and thirty five thousandeths

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g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds
dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

The number of ways of selecting 3 cards from 13 clubs is:

{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286

The number of ways of selecting 5 cards from 13 diamonds is:

{13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287

The number of ways of selecting 0 cards from 13 spades is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

Compute the number of ways to select 5 diamonds and 3 clubs as:

{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0
2 years ago
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