Answer:
here we work with factorials, so if we have a whole number N, then:
N! = N*(N-1)*.....*2*1
then, for the given expressions we have:
1) 6! = 6*5*4*3*2*1 = 720.
2) 3!*21 = (3*2*1)*21 = 216
3) and the last expression seems incomplete, i guess this is:
11! = 11*10*9*8*7*6*5*4*3*2*1 = 39,916,800
Answer:
a) The initial quantity is 2.9.
b) The initial quantity is 2.9.
c) The multiplier is 1.05 > 1, and thus, the quantity is growing.
Step-by-step explanation:
Exponential equations:
Have the following format:

In which A(0) is the initial amount and k is the multiplier.
If k > 0, the quantity is growing.
If k < 0, the quintity is decaying.
In this question:

a, b. The initial quantity is
P(0). So

The initial quantity is 2.9.
c. Is the quantity growing or decaying?
The multiplier is 1.05 > 1, and thus, the quantity is growing.
Answer:
416025 grade-point averages must be obtained so that the sample mean is within 0.006 of the population mean. But this size too big and is not practical.
Step-by-step explanation:
Minimum required grade-point averages can be found using the formula
N≥
where
- N is the sample size
- z is the corresponding z-score in 99% confidence level (2.58)
- s is the standard deviation (1.5)
- ME is the margin of error (0.006)
Putting these numbers in the formula we get
N≥
=416025
Answer:
Just pick 2 coins to compare (I mean the directions say compare 2).
Step-by-step explanation: