The direction vector of the line
L: x=1+t, y=4t, z=2-3t
is <1,4,-3>
which is also the required normal vector of the plane.
Since the plane passes through point (-5,9,10), the required plane is :
Π 1(x-(-5)+4(y-9)-3(z-10)=0
=>
Π x+4y-3z=1
Answer:
C. This was hard to do when I had this question
The prime factores are 7,2,2,2
The measure of the interior angles would be 120°, and they would all add up to be 720°
