Ask question

Ask question

All categories

2 years ago

14

What is 17 x 3 please help me

2 answers:

amm18122 years ago

5 0

The first thing that you need to do is multiply 10 times 3 that gives you 30 and then you need to multiply 7 times 3 and gives you 21 and then you add both numbers and the answer is 51.

Yanka [14]2 years ago

5 0

The answer is 61 hope that helps

You might be interested in

11 1/2 and 13 3/4 is?

Tpy6a [65]

This would depend on what you are asking for.

If you are adding the two numbers(which the word and is implying) you’re answer is 25 1/4.

You get this by finding a common denominator. In this case, that can be 4.

Turn 1/2 in to 2/4.

Next, you add 11 and 13 to get 24.

Then, you’ll add 2/4 and 3/4. You will get 1 1/4

Add 24 and 1 1/4. You have your answer of 25 1/4

5 0

3 years ago

Solve:C=10d + 5n for n

katovenus [111]

$n = - 2d + \frac{c}{5}$
hope this helps

5 0

2 years ago

Find the volume of the square pyramid and round to the

Brrunno [24]

The answer is to multiply

3 0

2 years ago

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

2 years ago

3x -4y = 13 y = -3x-7

Yuki888 [10]

Step-by-step explanation:

3x-4y=13

y=-3x-7

3x-4(-3x-7)=13

3x+12x+28=13

15x=-15

x= -1

y= -3x-7 = 3-7= -4

( -1, -4)

8 0

3 years ago