HELP HELP HELP PLS HELP ME I WILL GIVE YOU ALL 5 STARS!

Please help me with this and thank you

hichkok12 [17]

Answer:

16/3 or 5 1/3

Step-by-step explanation:

Because 2/3 * 8 = 16/3.

16/3 simplified is 5 1/3

4 0

3 years ago

Read 2 more answers

Use the given graph to determine the period of the function. 1 & 2 plz

White raven [17]

The period of the function is that distance where the function becomes equal again.
We have then:
Part 1:
The period of the function is:
T = 3
Part 2:
The period of the function is:
T = 4
Answer:
The period of functions 1 and 2 respectively are:
T = 3
T = 4

6 0

3 years ago

Calculate the l4 approximation for f(x) = cos2(x) on 8 , 2 . (round your answer to four decimal places.) l4 =

BaLLatris [955]

The solution for l4 is mathematically given as

L_{4}=0.5431

<h3>What is the solution for l4?</h3>

$&\text { Given } f(x)=a \cos ^{2}(x) \quad\left[\frac{\pi}{8}, \frac{\pi}{2}\right] \text { \& } n=4\\\\&\Delta a=\frac{b-a}{n}=\frac{\pi / 2-\pi / 8}{9}=\frac{3 \pi}{32}\\\\&x_{0}=\pi / 8, x_{1}=\frac{\pi}{8}+\frac{3 \pi}{32}=\frac{7 \pi}{32}\\\\&x_{2}=\frac{5 \pi}{16}, \quad x_{3}=\frac{13 \pi}{32}, x_{4}=\pi / 2\\\\&f\left(x_{0}\right)=f(1 / 8)=0.8535\\$

$&f\left(x_{1}\right)=f\left(\frac{7 \pi}{32}\right)=0.5975\\\\\&f\left(x_{2}\right)=f\left(\frac{5 \pi}{16}\right)=0.3086\\\\\&f\left(a_{3}\right)=f\left(\frac{13 \pi}{32}\right)=0.0842\\\\\&L_{4}=\sum_{k_{0}^{=0}}^{3} f\left(x_{k}\right) \Delta x\\\\&=\Delta \\\\x\left[f\left(x_{0}\right)+f\left(x_{1}\right)+f\left(x_{2}\right)+f\left(x_{3}\right)\right]\\\\\&=\frac{3 \pi}{32}[0.8535+0.5975+0.3056+0.0842]\\\\&L_{4}=0.5431$

Read more about approximation

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The complete Question is attached below

3 0

2 years ago

Diagram shows the composite solid formed by a cuboid and a right prism. Trapezium LMNP is the uniform cross section of the prism

kherson [118]

Answer:

MN = 7 cm

Step-by-step explanation:

Well the volume we can separate into pieces

first the ABCDEFGH (? you know this cuboid)

which has a volume of

$V = AB\cdot BC\cdot CH\\\\V = 3*6*(3+JY+4)$

if you ask where does the 4 come from

it comes from LP = KB = YC and JY + YC =JC

so

$V = 18(7+MX)$

this is because JY = MX

the other volume is of BCNPKLXY (hope you understand which one)

and the volume is

$V = BP*PN*NX\\\\V=8*6*4\\\\V = 192$

and the last one is KYXLMJ (the top "triangle")

the volume is

$V = \frac{LX*XM}{2}*LK\\\\V = \frac{6*MX}{2}*8\\\\V= 6*4*MX\\\\V=24MX$

so now add them up

and has to equal 444

$V_T = 18(7+MX)+192+24MX\\\\V_T = 126+18MX+192+24MX\\\\V_T = 318+42MX\\\\444=318+42MX\\\\444-318=42MX\\\\126=42MX\\\\MX = 3$

and finally we know that MN = MX + XN = 3+4 = 7

so here is our answer MN = 7 cm

a couple of notes

$1.\:\angle LXM = 90\\\\2.\:\angle KYX = 90$

3. the units don't matter due to the fact that everything is in cm

4. see the picture below to get a better idea of which prism I am talking of

5. tell me if you have questions :D

8 0

3 years ago

Madeline is standing 2x−4 feet from the base of a tree. The height of the tree is 5x+6 feet. Find the equation that shows the st

klemol [59]

Answer:

Required equation is $\sqrt{(2x-4)^2+(5x+6)^2}$ .

Step-by-step explanation:

Given,

Height of the tree=5x+6

Distance from feet of the tree=2x-4

To find straight distance from feet of Madeline to top of the tree.

Let the tree as y-axis and distance from base along x-axis. Then the distence of straight line from foot of Madeline to top is become the hypotenuse of the triangle. Thus if we let,

Distance from feet of Madeline to top of tree= p, then, according to law of finding third side of a triangle we get,

$p^2=(\textit{distance from base})^2+(\textit{height of tree})^2$

$\therefore p=\sqrt{(2x-4)^2+(5x+6)^2}$

Hence the result.

5 0

3 years ago