Step-by-step explanation:
Here is your answer
http://www.lasesp.com/article/16336607434947849/Surprise_Gift
Length x Width = Area
In your case, you'd want to flip around the equation.
100+x=900
900 divided by 100 is 9, so your width would be 9 Yards.
First, write an equation system based on the problem
An equation for "the perimeter of a rectangle is 70 in" can be written as following
∴ 2l + 2w = 70 <em>(first equation)</em>
An equation for "the length is 11 in more than its width" can be written as following
∴ l = w + 11 <em>(second equation)</em>
Second, solve the equation by substitution method o find the dimension of the rectangle.
Substitute/plug l as (w+11) into the first equation
2l + 2w = 70
2(w + 11) + 2w = 70
2w + 22 + 2w = 70
4w + 22 = 70
4w = 70 - 22
4w = 48
w = 48/4
w = 12
The width of the rectangle is 12 in
Substitute w with 12 to the second equation
l = w + 11
l = 12 + 11
l = 23
The length of the rectangle is 23 in
Third, find the area of the rectangle
a = l × w
a = 23 × 12
a = 276
The area of the rectangle is 276 in²
Area of a triangle is 1/2 x base x height:
Area = 1/2 x 8 x 20.5 = 82 square cm.
It is hone-half the area of a rectangle with dimensions 20.5 by 8 cm.
40m+35=
Step-by-step explanation:
I'm not sure but I think it is this
40m+35=
