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Stella [2.4K]
3 years ago
8

Help me solve for X I forgot how to this

Mathematics
2 answers:
alexgriva [62]3 years ago
6 0

Step-by-step explanation:

hope it helps you.........

lana [24]3 years ago
3 0

Answer:

here \: is \: your \: solution :  -  \\  \\ here \: is \: a \: right \: traingle \: with \\  \\ base \:  = 52 \: units \\  \\ hypotenuse \:  = 65 \: units \\  \\ perpendicular \:  =  {?} \\  \\ we \: need \: to \: find \: perpendicular \\  \\ by \: using \: pythagorus \: theorem :  -  \\  \\ perpendicular ^{2}  \:  = base ^{2}  + perpendicular ^{2}  \:  \\  \\ perpendicular^{2}  \:  = 65 {}^{2}  - 52 {}^{2}  \\  \\ perpendicular {}^{2}  = (4225 - 2704) \\  \\ perpendicular {}^{2} = 1521 \\  \\ perpendicular =  \sqrt{1521}  \\  \\ perpendicular = 39 \: units \:  \\  \\ hope \: it \: helps \: you \:

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Answer:

Greatest number of newspaper ads = 59

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Step-by-step explanation:

It is given that we should buy at least 5 newspapers for every 3 television ads.

So, after purchasing 3 television ads, we can buy any number of television ads but the number should be greater than 5.

Since, the maximum is 62, we can buy 59 newspaper ads. (Note that we have already bought 3 television ads).

For every 3 television ads, we should buy 5 newspaper ads. So,

For the purchase of 3 television ads, we should buy the minimum of 5 newspaper ads.

For the purchase of 2(3) television ads, we should buy the minimum of 2(5) newspaper ads.

For the purchase of 3(3) television ads, we should buy the minimum of 3(5) newspaper ads.

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For the purchase of 7(3) = 21 television ads, we should buy the minimum of 7(5) = 35 newspaper ads.

So, totally 21+35 = 56 ads.

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yanalaym [24]
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