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3 years ago

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7) While having an existential crisis you lay on the floor to stare at the ceiling. The normal force you experience from the gro

und is likely equal to...
A The parallel component of the your weight
B Your weight
C The friction between the you and the ground
D Your mass

2 answers:

Vlad [161]3 years ago

7 0

Answer:

kkk

Explanation:

vazorg [7]3 years ago

6 0

Answer:

The correct answer is B. your weight

Explanation:

Newton's third law states that every action has an equal and opposite reaction. You may not think this, but when you're standing on the floor, you are exerting a force against the floor: your weight, caused by gravity, is pulling you down. The floor is reacting by pushing back: we call this force the reaction force. -Google

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Two campers dock a canoe. One camper has a mass of 100.0 kg and moves forward at 3.0 m/s as he leaves the canoe to step onto the

KengaRu [80]

Answer:

V = -1.33 m/s

Explanation:

Given,

The mass of the camper, m = 100 kg

The velocity of the camper, v = 3.0 m/s

The combined mass of canoe and another camper, M = 225 kg

The velocity of the combined canoe and another camper, V = ?

According to the law of conservation of momentum,

MV + mv = 0 (Since the initial momentum of the dock is 0)

V = -mv/M

= -100 x 3/225

= -1.33 m/s

The negative sign indicates that the combined objects moves opposite to that of the camper.

Hence, the velocity of the combined canoe and camper is, V = -1.33 m/s

6 0

4 years ago

Help I need an answer!

Umnica [9.8K]

You apparently haven't noticed yet . . .

The moon rises in the East, moves across the sky, and sets
in the West, just like the sun and everything else in the sky.

It takes the moon about 12 hours and 25 minutes to go from
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49 minutes later. So each day, the moon rises about 49 minutes
later than it rose on the previous day.

In order to describe the direction and height of the moon in the sky,
you need to tell the date and the time, and also the latitude on Earth
from which you observed it. And wherever the moon was in the sky
at that time, it was in a noticeably different place 30 minutes later.

Just like the sun.

5 0

3 years ago

Two pieces of clay are moving directly toward each other. When they collide, they stick together and move as one piece. One piec

Wittaler [7]

Answer:

The fraction of the total initial kinetic energy is lost during the collision is $\dfrac{11}{17}\ J$

Explanation:

Given that,

Mass of one piece = 300 g

Speed of one piece = 1 m/s

Mass of other piece = 600 g

Speed of other piece = 0.75 m/s

We need to calculate the final velocity

Using conservation of energy

$m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v$

Put the value intro the formula

$300\times10^{-3}\times1+600\times10^{-3}\times(0.75)=(300\times10^{-3}+600\times10^{-3})v$

$v=\dfrac{00\times10^{-3}\times1+600\times10^{-3}\times(-0.75)}{(300\times10^{-3}+600\times10^{-3})}$

$v=-0.5\ m/s$

We need to calculate the total initial kinetic energy

Using formula of kinetic energy

$K.E_{i}=\dfrac{1}{2}m_{1}v_{1}^2+\dfrac{1}{2}m_{2}v_{2}^2$

Put the value into the formula

$K.E_{i}=\dfrac{1}{2}\times300\times10^{-3}\times1^2+\dfrac{1}{2}\times600\times10^{-3}\times(0.75)^2$

$K.E_{i}=0.31875\ J$

We need to calculate the total final kinetic energy

Using formula of kinetic energy

$K.E_{f}=\dfrac{1}{2}(m_{1}+m_{2})v^2$

Put the value into the formula

$K.E_{f}=\dfrac{1}{2}\times(300\times10^{-3}+600\times10^{-3})\times(-0.5)^2$

$K.E_{f}=0.1125\ J$

We need to calculate the energy lost during the collision

Using formula of energy lost

$energy\ lost=\dfrac{0.31875-0.1125}{0.31875}$

$energy\ lost=\dfrac{11}{17}\ J$

Hence, The fraction of the total initial kinetic energy is lost during the collision is $\dfrac{11}{17}\ J$

3 0

4 years ago

A lump of clay whose rest mass is 4 kg is travelling at three-fifths the speed of light when it collides head-on with an identic

Harman [31]

Answer:

mass of the composite lump is 10 kg

Explanation:

given data

mass = 4 kg

to find out

mass of composite lump

solution

we know energy is conserved so

so m1 = m2 = m0 that is 4kg

and

E(1) release+ E(2) release = E(1,2) rest

so γ(1)m(1)c² + γ(2)m(2)c² = Mc² ..........................1

that why here

|v(1)| = |v(2)| = 3/5 c ......................2

and

γ = 1 / √(1 − v²/c²) .......................3

put here v = 3 and c is 5

γ = 1 /√(1 − 9/25)

γ = 5/4

so

γ(1) = γ(2) = γ = 5/4

so from equation 1

γ(1)m(1)c² + γ(2)m(2)c² = Mc²

M = 2γm0

M = 2(5/4 )(4)

M = 10 kg

so mass of the composite lump is 10 kg

7 0

4 years ago

A 14000N car traveling at 25m/s rounds a curve of radius 200m. Find the following: a. The centripetal acceleration of the car.

tamaranim1 [39]

Answer:

Explanation:

Given

Weight of car $W=14,000\ N$

mass of car $m=\frac{14,000}{9.8}=1428.57\ N$

velocity of car $v=25\ m/s$

radius $r=200\ m$

(a)Centripetal acceleration is given by

$a_c=\frac{v^2}{r}$

$a_c=\frac{25^2}{200}$

$a_c=3.125\ m$

(b)Force that provide centripetal acceleration

$F=F_c=\frac{mv^2}{r}$

$F=\frac{1428.57\times 25^2}{200}$

$F=4464.285\ N$

(c)Friction force between car and tires is given by

$=\mu N$

where $\mu$ =coefficient of static friction

N=normal reaction

Centripetal force will balance the friction force

$F_c=F_r$

$4464.285=\mu \times 1428.57\times 9.8$

$\mu =0.318$

6 0

3 years ago

Read 2 more answers