Answer:
5308.34 N/C
Explanation:
Given:
Surface density of each plate (σ) = 47.0 nC/m² = 
Separation between the plates (d) = 2.20 cm
We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:
Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,
Now, plug in for 'σ' and 
for 
and solve for the electric field. This gives,
Therefore, the electric field between the plates has a magnitude of 5308.34 N/C
Their final velocity is 0.48 m/s.
We can use conservation of momentum to calculate the magnitude of the final velocity.
Momentum before collision is equal to the momentum after collision
m1v1+m2v2=(m1+m2)v
here, v is final velocity , assuming right side velocity as positive, and left side velocity as negative.
14*(-1.1)+18*(0)=(14+18)v
v=-0.48 m/s
Here, negative sign indicates that they both will move in left direction.
<span>23 hours 56 minutes and 4 seconds</span>
A false dalse true true false and thats a;ll i know
