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Nina [5.8K]
3 years ago
14

The brain is most active during which portion each sleep cycle

Physics
2 answers:
s2008m [1.1K]3 years ago
7 0
Its during REM sleep. hope this helped
kotegsom [21]3 years ago
3 0
R.E.M
Rapid Eye Movment
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An open rectangular tank 1 m wide and 2 m long contains gasoline to a depth of 1 m. If the height of the tank sides is 1.5 m, wh
lara [203]

Answer:

a_y = 4.9\ m/s^2

Explanation:

Given,

Width of rectangular tank, b = 1 m

Length of the tank, l = 2 m

height of the tank, d = 1.5 m

Depth of gasoline on the tank, h = 1 m

\dfrac{dz}{dy}=-\dfrac{1.5-1}{1}

\dfrac{dz}{dy}=-0.5

The differential form with the acceleration

\dfrac{dz}{dy}=\dfrac{-a_y}{a_z + g}

-0.5=-\dfrac{a_y}{a_z + g}

acceleration in z-direction = 0 m/s²

g = 9.8 m/s²

a_y is the horizontal acceleration of the gasoline.

0.5=\dfrac{a_y}{0 + 9.8}

a_y = 9.8\times 0.5

a_y = 4.9\ m/s^2

Hence, Horizontal acceleration of the gasoline before gasoline would spill is equal to 4.9 m/s²

3 0
3 years ago
a car moving at 5 m/s accelerates at a rate of 10 m/s2 for 25 seconds. How far does it move during this time?
Alexus [3.1K]

Answer:

t is time in s For example, a car accelerates in 5 s from 25 m/s to 3 5m/s. Its velocity changes by 35 - 25 = 10 m/s. Therefore its acceleration is 10 ÷ 5 = 2 m/s2

Explanation:

3 0
3 years ago
Witch will delsove faster 1 gram of sugar or 1 gram of salt
natka813 [3]

Answer:

Sugar dissolves faster than salt

4 0
3 years ago
A cylinder with a piston contains 0.200 mol of oxygen at 2.00×105 Pa and 360 K . The oxygen may be treated as an ideal gas. The
ikadub [295]

Answer:

A. W=600\ J

B. Q=2112\ J

C. \Delta U=1512\ J

D. W=0\ J

Explanation:

Given:

  • no. of moles of oxygen in the cylinder, n=0.2
  • initial pressure in the cylinder, P_i=2\times 10^5\ Pa
  • initial temperature of the gas in the cylinder, T_i=360\ K

<em>According to the question the final volume becomes twice of the initial volume.</em>

<u>Using ideal gas law:</u>

P.V=n.R.T

2\times 10^5\times V_i=0.2\times 8.314\times 360

V_i=0.003\ m^3

A.

<u>Work done by the gas during the initial isobaric expansion:</u>

W=P.dV

W=P_i\times (V_f-V_i)

W=2\times 10^5\times (0.006-0.003)

W=600\ J

C.

<u>we have the specific heat capacity of oxygen at constant pressure as:</u>

c_v=21\ J.mol^{-1}.K^{-1}

Now we apply Charles Law:

\frac{V_i}{T_i} =\frac{V_f}{T_f}

\frac{0.003}{360} =\frac{0.006}{T_f}

T_f=720\ K

<u>Now change in internal energy:</u>

\Delta U=n.c_p.(T_f-T_i)

\Delta U=0.2\times 21\times (720-360)

\Delta U=1512\ J

B.

<u>Now heat added to the system:</u>

Q=W+\Delta U

Q=600+1512

Q=2112\ J

D.

Since during final cooling the process is isochoric (i.e. the volume does not changes). So,

W=0\ J

7 0
3 years ago
A vector makes an angle of 30° with the positive x-axis.
kkurt [141]

Answer:

W = 112.58 N-unit

Explanation:

Given:

- Force F = 10 N

- Angle Q of force with x axis: 30 degrees

- distance to be moved d = 13 units along + x axis

Find:

Work Done by the force F:

Solution:

The work by force in positive x direction can only be done if the both the direction of distance traveled and direction of force are parallel vectors. Hence we compute the component of Force F in x direction F_x:

                                       F_x = F*cos(Q)

                                       F_x = 10*cos(30)

                                       F_x = 8.66 N

        Hence,

                                  Work Done by force

                                        W = F_x * d

                                       W = 8.66 * 13

                                  W = 112.58 N-unit

5 0
3 years ago
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