Answer: c) Yes, since the choice of the zero of potential energy is arbitrary.
Explanation:
Potential energy depends on the frame in which you are looking at the system.
For example, the potential energy of a lifted object can be written as:
U = mgh
where m is the mass, g is the gravitational acceleration and h is the height of the object.
But the height depends on where we have the zero if the zero is in the ground, then and h = 5m, then the potential energy is positive, but the 0 is the ground of a cliff, and the object is falling down the cliff, then we will have a negative value for h, which implies that we have negative potential energy.
This means that if we want to make the potential energy equal to zero, we must apply kinetic energy to the object (for example, grabbing it and throwing it upwards). On the other hand, if the potential energy is positive, this means that the object will "produce" kinetic energy as the potential energy starts to decrease. For example, an object that is dropped from a three (with an initial kinetic energy of zero) and only potential energy, and as the object falls to the ground the potential energy goes to zero and transforms completely in kinetic energy.
<em>"A less massive object can never have more momentum than a more massive object."</em>
That statement is FALSE, because momentum doesn't only depend on mass alone. It also depends on the speed with which the mass is moving. If the less massive object is moving at a tremendous speed, then it's quite possible for it to have more momentum than a more massive object.
A nice example is: <em>A brick wall.</em> The brick wall is not moving at all. Its speed is zero, so it has NO momentum. An ant crawling along on top of the brick wall has more momentum than the brick wall itself has.
Answer:
static friction
Explanation:
As I mentioned before static is just the object is started to move if it kentic it is moving
The independent (or manipulated) variable is something that the experimenter purposely changes or varies over the course of the investigational
there is no motion in the direction of the force, then no work is done by that force. ... But the work done on the box is zero since by moving in a straight line at constant speed, its energy is remaining the same.
