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2 years ago

Which compound contains a radical

Chemistry

2 answers:

slamgirl [31]2 years ago

6 0

The compound that contains a radical is called NaOH.

Explanation:

Radical, also called Free Radical, in chemistry, a fragment that contains at trivial one unpaired electron. Most molecules include even numbers of electrons, and the covalent chemical bonds including the atoms commonly within a molecule normally consist of pairs of electrons jointly shared by the atoms combined by the bond.

Gala2k [10]2 years ago

6 0

<span>The compound that contains a radical is called NaOH.</span>

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2 years ago

Hc2h3o2(aq)+h2o(l)⇌h3o+(aq)+c2h3o−2(aq) kc=1.8×10−5 at 25∘c part a if a solution initially contains 0.260 m hc2h3o2, what is the

Cloud [144]

Answer : The equilibrium concentration of $H_3O^+$ at $25^oC$ is, $2.154\times 10^{-3}m$ .

Solution : Given,

Equilibrium constant, $K_c=1.8\times 10^{-5}$

Initial concentration of $HC_2H_3O_2$ = 0.260 m

Let, the 'x' mol/L of $H_3O^+$ are formed and at same time 'x' mol/L of $HC_2H_3O_2$ are also formed.

The equilibrium reaction is,

$HC_2H_3O_2(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+C_2H_3O_2^-(aq)$

Initially 0.260 m 0 0

At equilibrium (0.260 - x) x x

The expression for equilibrium constant for a given reaction is,

$K_c=\frac{[H_3O^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}$

Now put all the given values in this expression, we get

$1.8\times 10^{-5}=\frac{(x)(x)}{(0.260-x)}$

By rearranging the terms, we get the value of 'x'.

$x=2.154\times 10^{-3}m$

Therefore, the equilibrium concentration of $H_3O^+$ at $25^oC$ is, $2.154\times 10^{-3}m$ .

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2 years ago

Pleaseee help it’s 20 points

Julli [10]

I’m pretty sure it’s nitrogen and oxygen but i’m not positive

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3 years ago

Read 2 more answers

Someone help please i am stuck on this

daser333 [38]

Answer:

33.5

Explanation:

the lowest point which is 33.5

pls mark brainlest

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3 years ago

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