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Degger [83]
2 years ago
9

Cells can use the glucose directly, without breaking it down, to carry out cellular processes. True or False?

Chemistry
1 answer:
Akimi4 [234]2 years ago
6 0

Answer:

False

Explanation:

Glucose is a substrate which undergoes various chemical reactions in the mitochondria to produce ATP, which is the universal energy carrier.

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Alpha has the greatest mass- A.

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What do the roman numberals mean?
Bezzdna [24]

Explanation:

c I think I am not sure so yh

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3 years ago
How many calories of heat were added to 347.9 g of water to raise its temperature from 25oC to 55oC?
saw5 [17]

Answer:

10437calories

Explanation:

The following data were obtained from the question given:

M = 347.9g

C = 4.2J/g°C

T1 = 25°C

T2 = 55°C

ΔT = 55 — 25 = 30°C

Q =?

Q = MCΔT

Q = 347.9 x 4.2 x 30

Q = 43835.4J

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4.2J = 1 calorie

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5 0
2 years ago
Calculate the fraction of atoms in a sample of argon gas at 400 K that have an energy of 10.0 kJ or greater.
nikdorinn [45]

Answer:

The answer to this can be arrived at by clculating the mole fraction of atoms higher than the activation energy of 10.0 kJ by pluging in the values given into the Arrhenius equation. The answer to this is 20.22 moles of Argon have energy equal to or greater than 10.0 kJ

Explanation:

From Arrhenius equation showing the temperature dependence of reaction rates.

K = Ae^{\frac{Ea}{RT} } where

k = rate constant

A = Frequency or pre-exponential factor

Ea   =       energy of activation

R = The universal gas constant

T = Kelvin absolute temperature

we have

f = e^{\frac{Ea}{RT} }

Where

f = fraction of collision with energy higher than the activation energy

Ea = activation energy = 10.0kJ = 10000J

R = universal gas constant = 8.31 J/mol.K

T = Absolute temperature in Kelvin = 400K

In the Arrhenius equation k = Ae^(-Ea/RT), the factor A is the frequency factor and the component e^(-Ea/RT) is the portion of possible collisions with high enough energy for a reaction to occur at the a specified temperature  

Plugging in the values into the equation relating f to activation energy we get

f = e^{\frac{10000J}{(8.31J/((mol)(K)))(400K)} } or f = e^{3.01} = 20.22 moles of argon have an energy of 10.0 kJ or greater

5 0
3 years ago
Nonmetals are excellent conductors of heat and electricity.<br> a. True<br> b. False
weeeeeb [17]
It's False.
Only metals can be conductors of heat and electricity.
4 0
3 years ago
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