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elixir [45]
3 years ago
11

Which is the graph of f(x) = -(x + 3)(x + 1)?

Mathematics
1 answer:
Bas_tet [7]3 years ago
4 0

Answer:

See attachment

Step-by-step explanation:

A function is given to us and we need to tell which graph represents the given function. The function given to us is,

\tt: \implies f(x) = -( x + 3 )( x + 1 )

Let's find out at which points do the graph Intersects x axis / finding the roots. For that substitute f(x) = 0 , we have ,

\tt: \implies  -(x +3)( x + 1 ) = 0

Equate each factor by 0 ,

\tt: \implies \boxed{\blue{ \tt x = -1,-3 }}

Therefore the graph will intersect x axis at x is equal to -1 and x is equal to -3 .

On looking at the given graphs in the options the second graph intersects x axis at -1 and -3 .

<u>Hence</u><u> </u><u>the </u><u>second</u><u> </u><u>option</u><u> </u><u>is </u><u>correct</u><u> </u><u>.</u><u> </u>

{ See attachment }

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3 years ago
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Answer:

\dfrac{2m -1}{5}

Step-by-step explanation:

Since we have common denominators inside the parentheses, we can combine the denominators. Then, we get the following expression:

2\huge\text{(}\dfrac{1}{5} m - \dfrac{2}{5} \huge\text{)} + \dfrac{3}{5}

2\huge\text{(}\dfrac{m - 2}{5} \huge\text{)} + \dfrac{3}{5}

Now, we can multiply the expression inside the parentheses by 2.

\huge\text{(}\dfrac{2m - 4}{5} \huge\text{)} + \dfrac{3}{5}

Since the expression inside the parentheses cannot be <u>simplified further</u>, we can open the parentheses and simplify the expression.

\dfrac{2m - 4}{5}  + \dfrac{3}{5}

We can combine the denominators as the denominators are the same.

\dfrac{2m - 4 + 3}{5}

Finally, we can simplify -4 + 3.

\dfrac{2m -1}{5}

Therefore, the simplified expression is (2m - 1)/5.

Learn more about combining like terms: brainly.com/question/13080103

5 0
2 years ago
HELP!!!!!! I believe its B but I am not sure! :(
n200080 [17]

Answer:

A

Step-by-step explanation:

When solving for x as an exponent, we need to use logarithms in order to undo the operation and rearrange the terms. We use log rules to bring down the exponent and solve. Logarithms are the inverse operations to exponents and vice versa. We have one special kind of logarithm called the natural logarithm whose base is e. We write it as ln. Since our base is e here, we will use the natural logarithm to rearrange and isolate x.

e^{4x-1} =3

We begin by applying the natural logarithm to each side.

ln(e^{4x-1}) =ln(3)

Log rules allow use to rearrange the exponent as multiplication in front of the log.

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ln e as an inverse simplifies to 1.

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We now apply the inverse operations for subtraction and multiplication.

4x-1+1=1+ln(3)\\4x=1+ln(3)\\\frac{4x}{4} =\frac{1+ln3}{4} \\x =\frac{1+ln3}{4}

Option A is correct.

5 0
3 years ago
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