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dezoksy [38]
3 years ago
15

The solution of this question

Mathematics
1 answer:
nata0808 [166]3 years ago
5 0

9514 1404 393

Answer:

  30°, 150°

Step-by-step explanation:

You know the answer to this because you have memorized the short table of trig function values.

  sin(θ) = 1/2 for θ = 30° and θ = 150°

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I am being asked to calculate and plot residuals and I don't know how my x values are 13.8, 18, 16,7, 18, 0.7, 21.9, 9.2, 19.5,
Igoryamba

Answer:

(13.8,1.42) (18,3.7)(16.7,3.21) and so on REMEMBER ITS (X,Y)

Step-by-step explanation:

3 0
3 years ago
If ur butt was split horizontally instead of vertically, would you clap when u ran down the stairs?
bixtya [17]

Answer:

yes cuz my butt is phat

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Simplify x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2
Artemon [7]

Answer:

2x^2 + 2y^2 + 2z^2

Step-by-step explanation:

x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2

First step is to put all the same ones together

( FYI, xy and yx is the same thing, just like how

2 x 3 and 3 x 2 is the same thing) this time I'll bracket the groups to make it easier on the eyes

(x^2 +x^2) + (xy - xy) +( y^2 + y^2) + (yz - yz) +

(z^2 +z^2) + (zx - zx)

2x^2 + 2y^2 + 2z^2

All the others just cancel themselves out, for example, xy-xy

When anything minus themselves it will become 0

7 0
3 years ago
Which number is equal to 10 to the power of neg 3
Shkiper50 [21]

Answer:

0.001

Step-by-step explanation:

4 0
3 years ago
QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is
soldi70 [24.7K]

Answer:

PQR = 20

Step-by-step explanation:

Given

Bisector: QS

PQS = 5x

RQS = 2x + 6

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

PQS = RQS

Substitute expressions for PQS and RQS

5x = 2x + 6

Collect Like Terms

5x - 2x = 6

3x = 6

Divide both sides by 3

x = 2

Solving for PQR;

PQR = PQS + RQS

PQR = 5x + 2x + 6

PQR = 7x + 6

Substitute 2 for x

PQR = 7 * 2 + 6

PQR = 14 + 6

PQR = 20

4 0
3 years ago
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