<h2> (1 ,2) (2,-3)</h2><h2>(x1,y1) (x2, y2)</h2>
<h2> Distance formual</h2>
<h2> √(x2-x1)^+(y2-y1)^</h2>
<h2>= √(2-1)^+(-3-2)^</h2><h2>= √(1)^+(-5)^ [here square root and </h2><h2> square get cancelled]</h2><h2>= (1)+(-5)</h2><h2>= 1-5</h2><h2>= - 4</h2>
You did not complete your question but I think this is what you are looking for. View the image.
2(8) 2×8 =16 that is how u do it
Let the no be X and Y
acc to ques....
x-y=9 .........1
xy=162 ..........2
substituting value from 1 in 2 we get;
x=9+y
[9+y][y] = 162
y^2+9y = 162
y^2 + 9y - 162=0
y^2 + 18y - 9y - 162=0
y[y+18] + 9[y+18]=0
[y+9][y+18}
y= -9.................................3
y= -18......................................4
case 1 :
y= -9
x = 9-9=0
case 2:
y= -18
x= 9-18 = -9
Answer:
6 square units is the answer
